位置14的问题 (Office Move) Consider the following activities: [table]
Activity | Description | Immediate predecessor(s) | Activity time (days) T | Find a location | --- | 8 U | Order furniture | T | 6 V | Interview | --- | 4 W | Hire and train | V | 9 X | Remodel | T | 11 Y | Setup furniture | U | 3 Z | Move in | W, X, Y | 1
| | |
[/table] Draw the project network. (Office Move) The critical path is ___.T-U-YT-U-ZT-X-ZT-Y-ZV-U-YV-U-ZV-W-YV-W-Z

Question

位置14的问题 (Office Move) Consider the following activities: [table]
Activity | Description | Immediate predecessor(s) | Activity time (days) T | Find a location | --- | 8 U | Order furniture | T | 6 V | Interview | --- | 4 W | Hire and train | V | 9 X | Remodel | T | 11 Y | Setup furniture | U | 3 Z | Move in | W, X, Y | 1
| |  | 
[/table] Draw the project network. (Office Move) The critical path is ___.T-U-YT-U-ZT-X-ZT-Y-ZV-U-YV-U-ZV-W-YV-W-Z

BlackTom AI · Accepted Answer

Critical path is the longest-duration chain of dependent activities from start to finish. Using the table, assign durations and immediate predecessors to each activity: T = Find a location (no predecessor) = 8 days; U = Order furniture (predecessor T) = 6 days; V = Interview (no predecessor) = 4 days; W = Hire and train (predecessor V) = 9 days; X = Remodel (predecessor T) = 11 days; Y = Setup furniture (predecessor U) = 3 days; Z = Move in (predecessors W, X, Y) = 1 day.

Step-by-step reasoning: list all feasible start-to-finish paths (ending at final activity Z) and compute their total durations.

1) Path T → U → Y → Z:
- T = 8
- U = 6
- Y = 3
- Z = 1
Total = 8 + 6 + 3 + 1 = 18 days

2) Path T → X → Z:
- T = 8
- X = 11
- Z = 1
Total = 8 + 11 + 1 = 20 days

3) Path V → W → Z:
- V = 4
- W = 9
- Z = 1
Total = 4 + 9 + 1 = 14 days

Check for other listed answer choices:
- T → U → Z: invalid because Z’s predecessors are W, X, Y; U does not lead directly to Z.
- V → U → Y or V → U → Z: invalid because U’s predecessor is T, so V → U is not allowed by precedence.
- V → W → Y: invalid because W does not lead to Y; Y’s predecessor is U.
So those options either violate precedence or do not end at the final activity.

Why T-X-Z is correct: among all valid start-to-finish routes, T → X → Z has the largest total duration (20 days), so it determines the project duration and is the critical path. Therefore the critical path is T-X-Z.

Final confirmation: the critical path T-X-Z matches the provided correct answer.

类似问题

When using Miro to plan a complex project, which capability would you need to obtain from another tool because Miro does not provide it natively?

Question6.2 (0.5 marks) The critical path is [select: , ABCDE, BDE, ACE]. ResetMaximum marks: 0.5 Flag question undefined

There is an activity in the project that has an early start (ES) on day 3, late start (LS) on day 13, early finish (EF) on day 9, and late finish (LF) on day 19. What is the most accurate interpretation of this activity?

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The critical path is:

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