Question textThe definite integral\displaystyle \int_0^{\frac{\pi}{2}} \sin^4(x)\cos^3(x)\,dx can be evaluated using the trigonometric identity\sin^2(x) + \cos^2(x)=1and then use of integration by substitution. This gives\displaystyle \int_0^{\frac{\pi}{2}} \sin^4(x)\cos^3(x)\,dx = \displaystyle \int_0^1 u^a - u^b\, du where a  and b  are positive integers.The final solution is of the form \dfrac{2}{A} where A  is an integer.Fill in the correct values for a,\,\,b and A.a = Answer 1 Question 29[input] b = Answer 2 Question 29[input] A = Answer 3 Question 29[input]多项填空题