Problem: Evaluate the integral∫cos(4x)cos(7x)dx.  Step-by-step solution: a) Look at the Rule above Example 3.13 in the textbook Links to an external site. . To evaluate the integral  ∫cos(7x)cos(4x)dx should we use equation (3.3), (3.4) or (3.5)?  [ Select ] Equation (3.5) Equation (3.4) Equation (3.3)   b) In this example, a=7  and b=4. Which of the following options is correct? [ Select ] Option I Option III Option II Option I:  ∫cos(7x)cos(4x)dx=∫( 1 2 cos(3x)− 1 2 cos(11x))dx      Option II:  ∫cos(7x)cos(4x)dx=∫( 1 2 cos(3x)+ 1 2 cos(11x))dx     Option III:  ∫cos(7x)cos(4x)dx=∫( 1 2 cos(11x)+ 1 2 cos(7x))dx       c) Now integrate your answer from (b). Which is the correct final answer to the problem? Option C Option A: ∫cos(7x)cos(4x)dx= 1 6 sin(3x)− 1 22 sin(11x)+C   Option B: ∫cos(7x)cos(4x)dx= 1 22 sin(11x)+ 1 14 sin(7x)+C      Option C: ∫cos(7x)cos(4x)dx= 1 6 sin(3x)+ 1 22 sin(11x)+C       Option D: ∫cos(7x)cos(4x)dx=− 3 2 sin(3x)− 11 2 sin(11x)+C      多重下拉选择题

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