Question texta) The Maclaurin series of [math: ex2] is [math: ex2=]Answer 1 Question 9[input] [math: +] Answer 2 Question 9[input][math: x] [math: +] Answer 3 Question 9[input][math: x2] [math: +] Answer 4 Question 9[input][math: x3] [math: +…]b) The Maclaurin series of [math: ∫0x6ln(1+t)sin(t)dt] is [math: ∫0x6ln(1+t)sin(t)dt=]Answer 5 Question 9[input] [math: +] Answer 6 Question 9[input][math: x] [math: +] Answer 7 Question 9[input][math: x2] [math: +] Answer 8 Question 9[input][math: x3] [math: +…]多项填空题
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Question texta) The Maclaurin series of \(e^{x^2}\) is \(e^{x^2} =\)Answer 1 Question 9[input] \(+\) Answer 2 Question 9[input]\(x\) \(+\) Answer 3 Question 9[input]\(x^2\) \(+\) Answer 4 Question 9[input]\(x^3\) \(+\ldots\)b) The Maclaurin series of \(\int_0^x 6\ln(1+t)\sin(t) dt \) is \(\int_0^x 6\ln(1+t)\sin(t) dt =\)Answer 5 Question 9[input] \(+\) Answer 6 Question 9[input]\(x\) \(+\) Answer 7 Question 9[input]\(x^2\) \(+\) Answer 8 Question 9[input]\(x^3\) \(+\ldots\)
Question texta) The Maclaurin series of \(e^{x^2}\) is \(e^{x^2} =\)Answer 1 Question 9[input] \(+\) Answer 2 Question 9[input]\(x\) \(+\) Answer 3 Question 9[input]\(x^2\) \(+\) Answer 4 Question 9[input]\(x^3\) \(+\ldots\)b) The Maclaurin series of \(\int_0^x 6\ln(1+t)\sin(t) dt \) is \(\int_0^x 6\ln(1+t)\sin(t) dt =\)Answer 5 Question 9[input] \(+\) Answer 6 Question 9[input]\(x\) \(+\) Answer 7 Question 9[input]\(x^2\) \(+\) Answer 8 Question 9[input]\(x^3\) \(+\ldots\)
Question texta) The Maclaurin series of [math: ex2] is [math: ex2=]Answer 1 Question 9[input] [math: +] Answer 2 Question 9[input][math: x] [math: +] Answer 3 Question 9[input][math: x2] [math: +] Answer 4 Question 9[input][math: x3] [math: +…]b) The Maclaurin series of [math: ∫0x6ln(1+t)sin(t)dt] is [math: ∫0x6ln(1+t)sin(t)dt=]Answer 5 Question 9[input] [math: +] Answer 6 Question 9[input][math: x] [math: +] Answer 7 Question 9[input][math: x2] [math: +] Answer 8 Question 9[input][math: x3] [math: +…]
Use the first two terms of the Maclaurin series for 1 4 + 𝑥 to estimate the value of 1 4 + 𝑥 when x=0.8 Enter your answer to two decimal places, rounding appropriately.
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