Question text 9Marks a) The Maclaurin series of [math: f(x)=2cos(x)]f(x) = 2\cos(x) is [math: f(x)=]Answer 1[input][math: +]Answer 2[input][math: x+]Answer 3[input][math: x2+⋯]x^2+\cdotsb) The Maclaurin series of [math: g(x)=6ln(1−x)]g(x) = 6\ln(1-x) is [math: g(x)=]Answer 4[input][math: +]Answer 5[input][math: x+]Answer 6[input][math: x2+⋯]x^2+\cdotsc) The Maclaurin series of [math: h(x)=2cos(3x)+6ln(1−x2)]h(x) = 2\cos(3x) + 6\ln(1-x^2) is[math: h(x)=]Answer 7[input][math: +]Answer 8[input][math: x+]Answer 9[input][math: x2+⋯]x^2+\cdotsPlease answer all parts of the question.Notes Report question issue Question 7 Notes多项填空题
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Question texta) The Maclaurin series of \(e^{x^2}\) is \(e^{x^2} =\)Answer 1 Question 9[input] \(+\) Answer 2 Question 9[input]\(x\) \(+\) Answer 3 Question 9[input]\(x^2\) \(+\) Answer 4 Question 9[input]\(x^3\) \(+\ldots\)b) The Maclaurin series of \(\int_0^x 6\ln(1+t)\sin(t) dt \) is \(\int_0^x 6\ln(1+t)\sin(t) dt =\)Answer 5 Question 9[input] \(+\) Answer 6 Question 9[input]\(x\) \(+\) Answer 7 Question 9[input]\(x^2\) \(+\) Answer 8 Question 9[input]\(x^3\) \(+\ldots\)
Question texta) The Maclaurin series of [math: ex2] is [math: ex2=]Answer 1 Question 9[input] [math: +] Answer 2 Question 9[input][math: x] [math: +] Answer 3 Question 9[input][math: x2] [math: +] Answer 4 Question 9[input][math: x3] [math: +…]b) The Maclaurin series of [math: ∫0x6ln(1+t)sin(t)dt] is [math: ∫0x6ln(1+t)sin(t)dt=]Answer 5 Question 9[input] [math: +] Answer 6 Question 9[input][math: x] [math: +] Answer 7 Question 9[input][math: x2] [math: +] Answer 8 Question 9[input][math: x3] [math: +…]
Question texta) The Maclaurin series of \(e^{x^2}\) is \(e^{x^2} =\)Answer 1 Question 9[input] \(+\) Answer 2 Question 9[input]\(x\) \(+\) Answer 3 Question 9[input]\(x^2\) \(+\) Answer 4 Question 9[input]\(x^3\) \(+\ldots\)b) The Maclaurin series of \(\int_0^x 6\ln(1+t)\sin(t) dt \) is \(\int_0^x 6\ln(1+t)\sin(t) dt =\)Answer 5 Question 9[input] \(+\) Answer 6 Question 9[input]\(x\) \(+\) Answer 7 Question 9[input]\(x^2\) \(+\) Answer 8 Question 9[input]\(x^3\) \(+\ldots\)
Question texta) The Maclaurin series of [math: ex2] is [math: ex2=]Answer 1 Question 9[input] [math: +] Answer 2 Question 9[input][math: x] [math: +] Answer 3 Question 9[input][math: x2] [math: +] Answer 4 Question 9[input][math: x3] [math: +…]b) The Maclaurin series of [math: ∫0x6ln(1+t)sin(t)dt] is [math: ∫0x6ln(1+t)sin(t)dt=]Answer 5 Question 9[input] [math: +] Answer 6 Question 9[input][math: x] [math: +] Answer 7 Question 9[input][math: x2] [math: +] Answer 8 Question 9[input][math: x3] [math: +…]
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