For the given program, how many cout statements will execute? void PrintShippingCharge(double itemWeight) { if ((itemWeight 0.0) && (itemWeight

Question

For the given program, how many cout statements will execute? void PrintShippingCharge(double itemWeight) { if ((itemWeight > 0.0) && (itemWeight <= 10.0)) { cout << (itemWeight * 0.75) << endl; } else if ((itemWeight > 10.0) && (itemWeight <= 15.0)) { cout << (itemWeight * 0.85) << endl; } else if ((itemWeight > 15.0) && (itemWeight <= 20.0)) { cout << (itemWeight * 0.95)<< endl; } } int main() { PrintShippingCharge(18); PrintShippingCharge(6); PrintShippingCharge(25); return 0; }

BlackTom AI · Accepted Answer

Because the function uses a mutually exclusive if - else if - else if chain, at most one cout executes during any single call to PrintShippingCharge. The relevant concepts are conditional evaluation (&& combines two boolean tests) and the behavior of an if/else if chain (once a true branch runs, the rest are skipped). 1) Relevant knowledge points and concepts - The expression (A && B) is true only if both A and B are true. - In an if / else if / else if chain, once one condition is true and its block runs, subsequent else if blocks are not evaluated. - Each cout inside a taken branch executes exactly once per function call. 2) Step-by-step reasoning for each call Call 1: PrintShippingCharge(18) - First condition: (18 > 0.0) && (18 <= 10.0) ⇒ true && false ⇒ false. So first branch not taken. - Second condition: (18 > 10.0) && (18 <= 15.0) ⇒ true && false ⇒ false. Not taken. - Third condition: (18 > 15.0) && (18 <= 20.0) ⇒ true && true ⇒ true. Third branch taken → cout executes once for this call. Call 2: PrintShippingCharge(6) - First condition: (6 > 0.0) && (6 <= 10.0) ⇒ true && true ⇒ true. First branch taken → cout executes once. Because it is an else-if chain, the other branches are skipped for this call. Call 3: PrintShippingCharge(25) - First condition: (25 > 0.0) && (25 <= 10.0) ⇒ true && false ⇒ false. - Second: (25 > 10.0) && (25 <= 15.0) ⇒ true && false ⇒ false. - Third: (25 > 15.0) && (25 <= 20.0) ⇒ true && false ⇒ false. - No branch is taken → no cout executes for this call. 3) Intermediate counts and final total - Call 1: 1 cout - Call 2: 1 cout - Call 3: 0 cout Total = 1 + 1 + 0 = 2 4) Why the correct answer is correct The if/else-if structure ensures only one possible cout per call, and evaluating the three provided inputs yields two calls that meet a branch condition. 5) Why other options are incorrect - "1": would imply only one of the three calls printed; but two calls match conditions. - "3": would be true only if all three calls printed; the third call (25) does not meet any condition. - "9": unrelated and impossible given one cout per taken branch and only three calls. 6) Conclusion The total number of cout statements executed is 2, which matches the provided answer.

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