If the input is 5, what is the output? int x; cin x; if (x

Question

If the input is 5, what is the output? int x; cin >> x; if (x < 10) { cout << "Live "; } else if (x < 20) { cout << "long "; } else if (x < 30) { cout << "and "; } cout << "prosper!";

BlackTom AI · Accepted Answer

Since x is 5, the condition x < 10 is true, so the first if branch executes and prints "Live " (including the trailing space), then the final cout prints "prosper!", producing "Live prosper!". 1) Relevant knowledge points and concepts - C++ if / else if control flow: the first true condition's block executes; subsequent else if blocks are skipped. - A lone cout after the conditional executes regardless of which branch ran. - String literals include any spaces they contain; "Live " has a trailing space that affects the final concatenated output. - No syntactic requirement for a final else; missing else is not a compiler error. 2) Step-by-step execution - int x; cin >> x; reads the integer 5, so x = 5. - Evaluate if (x < 10): 5 < 10 is true. - Execute the body of this if: cout << "Live "; outputs the characters L i v e and a space. - Skip the else if (x < 20) and else if (x < 30) blocks because the first if was true. - Execute the final statement cout << "prosper!"; which outputs p r o s p e r ! immediately after the already printed space. 3) Intermediate output steps (concatenation) - After first cout: output = "Live " - After final cout: output = "Live " + "prosper!" = "Live prosper!" 4) Why the correct answer is correct Because the first conditional is true for x = 5, its print statement runs; the subsequent cout outside the conditional always runs. Combined, they produce the single string "Live prosper!". 5) Why the other options are incorrect - "Live long": would require the second branch (x < 20) to run; it does not because the first if already matched. - "Error: The compiler will complain about a missing else statement": false — an else is optional and this code is syntactically valid. - "Live": incomplete because the program also prints "prosper!" afterward. 6) Conclusion The final output is "Live prosper!", which matches the provided correct answer.

If the input is 5, what is the output? int x; cin >> x; if (x < 10) { cout << "Live "; } else if (x < 20) { cout << "long "; } else if (x < 30) { cout << "and "; } cout << "prosper!";单项选择题

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