What is the coordination number, geometry and oxidation state of Ni in:

Question

BlackTom AI · Accepted Answer

There are six donor atoms bound to Ni: five NH3 ligands (each neutral) plus one bromide (Br−) coordinated to the metal. That gives coordination number = 6 and, for a six‑coordinate first‑row transition metal, the favored geometry is octahedral.

1) Relevant concepts
- Coordination number = number of donor atoms directly bonded to the metal.
- Geometry for coordination number 6 is most commonly octahedral.
- Oxidation state of the metal is found by summing charges: metal oxidation state + sum(ligand charges) = overall complex charge.

2) Step‑by‑step reasoning
- Count ligands in the drawn complex: five NH3 molecules (neutral ligands) and one coordinated Br (bromido, charge −1). That is 5 + 1 = 6 donor atoms → coordination number = 6.
- Six coordination implies octahedral geometry (typical arrangement unless otherwise specified by unusual ligand constraints).
- Determine oxidation state: the complex is shown inside brackets with a chloride (Cl−) outside the brackets. That means the complex ion carries a +1 charge (to balance the external Cl−).
- Let Ni oxidation state = x. Sum of ligand charges = 5×(0 for NH3) + (−1 for Br) = −1.
  So x + (−1) = +1 (complex charge), therefore x − 1 = +1 → x = +2.

3) Why the correct answer is correct
- The counted donors (5 NH3 + Br−) give CN = 6 and the typical arrangement is octahedral. Charge balance gives Ni in oxidation state +2.

4) Why other options are incorrect
- (a) 7, octahedral, +2: coordination number 7 is not supported by the drawing (only six donors present).
- (b) 6, square pyramidal, +3: square pyramidal corresponds to CN = 5, and oxidation state +3 contradicts charge balance.
- (d) 6, octahedral, +3: geometry is correct but oxidation state is wrong (charge balance gives +2).

Conclusion: coordination number 6, octahedral geometry, Ni oxidation state +2, matching answer c.

What is the coordination number, geometry and oxidation state of Ni in:单项选择题

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