A circuit has an applied voltage of 24 volts and a load consisting of a 10-ohm resistor in series with a 30-ohm resistor. What is the voltage drop across the 10-ohm resistor?

Question

BlackTom AI · Accepted Answer

To determine the voltage drop across the 10-ohm resistor, we start by finding the total resistance in the series circuit: R_total = 10 ohms + 30 ohms = 40 ohms.
Next, compute the current using Ohm's law for the entire circuit: I = V / R_total = 24 V / 40 ohms = 0.6 A.
The voltage drop across a specific resistor in a series circuit is I times that resistor's resistance. So, V_10ohm = I * R_10ohm = 0.6 A * 10 ohms = 6 V.
As a check, voltage division formula V_10ohm = (R_10ohm / R_total) * V = (10 / 40) * 24 V = 0.25 * 24 V = 6 V, which matches the previous calculation.
Therefore, the voltage drop across the 10-ohm resistor is 6 volts.

A circuit has an applied voltage of 24 volts and a load consisting of a 10-ohm resistor in series with a 30-ohm resistor. What is the voltage drop across the 10-ohm resistor?Single choice

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