What is the output? double CheckForFever (double temperature) { const double NORMAL_TEMP = 98.6; const double CUTOFF_TEMP = 95; double degreesOfFever; if (temperature NORMAL_TEMP) { degreesOfFever = temperature - NORMAL_TEMP; cout

Question

What is the output?

double CheckForFever (double temperature) {
   const double NORMAL_TEMP = 98.6;
   const double CUTOFF_TEMP = 95;
   double degreesOfFever;
   if (temperature > NORMAL_TEMP) { 
      degreesOfFever = temperature - NORMAL_TEMP;
      cout << "You have " << degreesOfFever << " degrees of fever."; 
   } 
   else if (temperature < CUTOFF_TEMP) {
      degreesOfFever = CUTOFF_TEMP - temperature;
      cout << "Your temperature is " << degreesOfFever << " below 95."; 
   }
   return degreesOfFever;
}
int main() {
   double bodyTemperature;
   double degreesOfFever;
   bodyTemperature = 96.0;
   cout << "Checking for fever...";
   degreesOfFever = CheckForFever(bodyTemperature);
   return 0;
}

BlackTom AI · Accepted Answer

Because bodyTemperature is 96.0 and NORMAL_TEMP is 98.6, the conditionals inside CheckForFever do not trigger any additional output; only the initial cout in main executes. 1) Relevant knowledge points and concepts - Execution order: main prints before calling the function. - Conditional checks: > and < comparisons determine which branch executes. - cout writes to standard output immediately; no implicit newline is added. - Returning a value does not produce output unless it is printed. 2) Step-by-step reasoning - main sets bodyTemperature = 96.0. - main executes cout << "Checking for fever..."; so the literal string "Checking for fever..." is sent to output. - main calls CheckForFever(96.0). 3) Intermediate comparisons (calculations) - Compare temperature > NORMAL_TEMP: 96.0 > 98.6? False. - Compare temperature < CUTOFF_TEMP: 96.0 < 95? False. - Since both conditions are false, neither of the cout statements inside CheckForFever runs. 4) Why the correct answer is correct - Only the cout in main produces visible output. The function makes no further cout calls because the temperature (96.0) is between 95 and 98.6. The returned degreesOfFever value is not printed in main, so it doesn't appear on output. 5) Why the other options are incorrect - "(Nothing is output)" is wrong because main explicitly prints "Checking for fever...". - Any option that includes "Your temperature is 2.6 below 95." is wrong because 96.0 is not below 95, so that branch never executes. - Options that append additional text to the initial string assume the function printed something; it does not. 6) Conclusion The only output produced is exactly: Checking for fever... This matches the provided correct answer.

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