What is the output? #include using namespace std; const double LB_PER_KG = 2.2; double KgsToLbs(double kilograms) { double pounds; pounds = kilograms * LB_PER_KG; return pounds; } int main() { double pounds; pounds = KgsToLbs(10); cout

Question

What is the output?

#include <iostream>
using namespace std;
const double LB_PER_KG = 2.2;
double KgsToLbs(double kilograms) {
  double pounds;  
  pounds = kilograms * LB_PER_KG;                
  return pounds;
}

int main() {
  double pounds;    
  pounds = KgsToLbs(10);
  cout << pounds;
  return 0;
}

BlackTom AI · Accepted Answer

10 kilograms multiplied by the conversion factor 2.2 yields 22 pounds.

1) Relevant knowledge points and concepts
- Global const variables (const double LB_PER_KG = 2.2;) are legal in C++ and provide a constant accessible to all functions; they do not cause a compiler error.
- Function parameters and local variables have local scope: the local variable pounds inside KgsToLbs and the local variable pounds inside main are distinct and do not conflict.
- The function KgsToLbs(double kilograms) returns a double value computed by multiplying the input by LB_PER_KG.
- cout << pounds; prints the double value to standard output.

2) Step-by-step reasoning
- main calls KgsToLbs(10). So the function parameter kilograms receives the value 10 (as a double).
- Inside KgsToLbs, pounds is computed as kilograms * LB_PER_KG.
- The computed pounds value is returned to main and stored in main’s local pounds variable.
- main then sends that value to cout, which prints it.

3) Calculation with intermediate steps
- kilograms = 10
- LB_PER_KG = 2.2
- pounds = kilograms * LB_PER_KG
- pounds = 10 * 2.2
- pounds = 22.0 (a double value; cout prints this as 22)

4) Why the correct answer is correct
- The arithmetic 10 × 2.2 equals 22, and the program prints the returned double. There are no syntax or scope errors in the code, so the computed value is output.

5) Why the other options are incorrect
- "No output: Global variable declared as const causes compiler error": Incorrect — const globals are valid C++.
- "No output: variable pounds declared into two functions causes compiler error": Incorrect — each pounds is a separate local variable in its own scope; this is allowed.
- "No output: LB_PER_KG causes a compiler error due to being outside any function": Incorrect — global variables (including const) may be declared outside functions.

6) Conclusion
The program prints 22, which matches the provided correct answer: 22.

What is the output? #include <iostream> using namespace std; const double LB_PER_KG = 2.2; double KgsToLbs(double kilograms) { double pounds; pounds = kilograms * LB_PER_KG; return pounds; } int main() { double pounds; pounds = KgsToLbs(10); cout << pounds; return 0; }单项选择题

类似问题

What is the output of the following program lines when embedded in a correct program that declares all variables to be of type char? a = ‘c’; b = a; c = ‘a’; cout << a << ‘b’ << c;

What is output? double MyFct(double a, double b) { return (a + b) / 2.0; } int main() { double x = 3.0; double y = 5.0; double z = 8.0; double t; t = MyFct(x, y); t = MyFct(t, z); cout << t << endl; return 0; }

Given the following function. To change the function to return the product instead of the sum, how many lines of code need to be changed? int Calculate(int a, int b) { return a + b; } int main() { cout << Calculate(3, 4); cout << Calculate(5, 2); cout << Calculate(6, 7); return 0; }

What is the output of the following program segment? double temp[5]; for (int i = 0; i < 5; i++) temp[i] = pow(i, 2.0) + 3; temp[0] = pow(temp[1], 3); temp[1] = temp[4] - temp[2]; temp[2] = temp[0] - 4; cout << temp[2] << endl;

Given the following function. To change the function to return the product instead of the sum, how many lines of code need to be changed? int Calculate(int a, int b) { return a + b; } int main() { cout << Calculate(3, 4); cout << Calculate(5, 2); cout << Calculate(6, 7); return 0; }

更多留学生实用工具

智能学习助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单