Which input value causes the loop body to execute a 2nd time, thus outputting "In loop" again? string s = "Go"; while ((s != "q") && (s != "Q")){ cout

Question

Which input value causes the loop body to execute a 2nd time, thus outputting "In loop" again? string s = "Go"; while ((s != "q") && (s != "Q")){ cout << "In loop" << endl; cin >> s; }

BlackTom AI · Accepted Answer

The while condition is (s != "q") && (s != "Q"), so the loop continues only when s is neither "q" nor "Q".

1) Relevant knowledge points and concepts
- In C++, string comparison with != and == is case-sensitive and compares full string content.
- The logical AND (&&) requires both operands to be true for the overall condition to be true.
- The loop prints "In loop" and then reads a new value for s; that new s is what determines whether a second iteration occurs.

2) Step-by-step reasoning
- Initially s = "Go". Evaluate condition: ("Go" != "q") is true AND ("Go" != "Q") is true, so the while condition is true and the loop enters its first iteration.
- First iteration: the program outputs "In loop" and then executes cin >> s to read a new input value.
- After input, the while condition is tested again using the newly read s. To get a second "In loop" printed, the condition must still be true (i.e., the new s must be neither "q" nor "Q").

3) Intermediate checks/examples
- If input is "Quit": ("Quit" != "q") → true; ("Quit" != "Q") → true; true && true → true → loop runs again (prints "In loop" a second time).
- If input is "q": ("q" != "q") → false; false && (...) → false → loop stops (no second print).
- If input is "Q": ("Q" != "q") → true; ("Q" != "Q") → false; true && false → false → loop stops.

4) Why the correct answer is correct
"Quit" is neither exactly "q" nor exactly "Q", so both comparisons are true and the && expression is true; therefore the loop condition remains true and the loop body executes a second time.

5) Why the other options are incorrect
- "\"q\" only": entering "q" makes (s != "q") false, so the loop stops (no second iteration).
- "\"Q\" only": entering "Q" makes (s != "Q") false, so the loop stops.
- "Either \"q\" or \"Q\"": either of those will terminate the loop rather than cause a second execution.

6) Conclusion
The input that causes the loop to execute a second time is "Quit", which matches the provided correct answer.

Which input value causes the loop body to execute a 2nd time, thus outputting "In loop" again? string s = "Go"; while ((s != "q") && (s != "Q")){ cout << "In loop" << endl; cin >> s; }单项选择题

类似问题

What is the output? int x = 18; while (x > 0) { // Output x and a space x = x / 3; }

What is the output? int x = 18; while (x > 0) { // Output x and a space x = x / 3; }

How many times will Python run the <body contents> inside the while loop before exiting? x = 1 y = 1 while y < 4: <body contents> y = y + 2

What's the value of total after running this code:

The following code will loop through the code and ultimately print out the numbers 1-11. Select the missing syntax from the TWO dropdown list boxes. i = 1 [ Select ] while as long as If else when i < [ Select ] i+1: 11: i: 0: 12: 1: print(i) i = i + 1

What type of control structure is shown below?

Dexter is planning to enter the following values into the program above (in the order shown). 5, 7, 3, 5, -1, 2 and 8. What will be displayed by the program?

Which control structure is shown in the pseudocode below?

更多留学生实用工具

智能学习助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单