e

Question

e <- 4
f <- e + 5
e <- 6
f

The output returned is 11.

BlackTom AI · Accepted Answer

To start, let's parse the code line by line and track how variables change and what gets printed.
Option 1: True. The claim is that the final value of f is 11. However, after the first two lines, e is 4 and f becomes e + 5, which evaluates to 9. Then the line e <- 6 reassigns e to 6, but this does not modify f, which already holds the value 9 from the previous step. Finally, the expression f evaluates to 9, not 11. Therefore, the statement that the output is 11 is incorrect.
Option 2: False. This is the correct evaluation of the code because f was computed before e was updated to 6, and f retains the 9 that came from the earlier e value (4) being used in the calculation. The later reassignment of e has no retroactive effect on f. Hence, the printed or returned value is 9, not 11.
Additional note: If someone misinterprets the sequence and thinks f would automatically reflect the new e value, they are assuming lazy or dynamic binding, which is not how this imperative sequence operates in R. The operations are executed in order, and f is bound to the result of e + 5 at the time f was created, independent of future changes to e.

e <- 4 f <- e + 5 e <- 6 f The output returned is 11.判断题

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