A graph of the function with equation [math: y=sin(x)] is transformed by- a dilation of factor 4 from the [math: y] -axis - a translation of [math: π2] \frac{ \pi }{2} units in the positive direction of the [math: x] -axis- a translation of 1 unit in the positive direction of the [math: y] -axisThe equation of the image is given by:单项选择题
A
A. [math: y=sin(14(x−π2))+1] y=sin( \frac{1}{4} (x- \frac{ \pi }{2} ))+1
B
B. [math: y=4sin((x−π2))+1] y=4sin( (x- \frac{ \pi }{2} ))+1
C
C. [math: y=sin(12(x+π2))−1] y=sin( \frac{1}{2} (x+ \frac{ \pi }{2} ))-1
D
D. [math: y=4sin((x+π2))−1] y=4sin( (x+ \frac{ \pi }{2} ))-1
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类似问题
The graph of [math: y=sin(x)] is reflected in the y-axis, then translated [math: π4] units left. Which of these equations gives the image of the transformed graph?
Question textThe circular function [math: f(x)=sin(x)] has been dilated in the [math: y] axis direction by a factor [math: 3]\displaystyle {3}, translated [math: π3]\displaystyle {\frac{\pi}{3}} units in the positive direction of the [math: x] axis and translated [math: 8]\displaystyle {8} units in the negative direction of the [math: y] axis. The resulted function is [math: f(x)]=[input] Check Question 1
Question textThe circular function [math: f(x)=sin(x)] has been dilated in the [math: y] axis direction by a factor [math: 6]\displaystyle {6}, translated [math: 2π3]\displaystyle {\frac{2\,\pi}{3}} units in the positive direction of the [math: x] axis and translated [math: 6]\displaystyle {6} units in the negative direction of the [math: y] axis. The resulted function is [math: f(x)]=[input] Check Question 1
Question textThe circular function [math: f(x)=sin(x)] has been dilated in the [math: y] axis direction by a factor [math: 4]\displaystyle {4}, translated [math: π4]\displaystyle {\frac{\pi}{4}} units in the positive direction of the [math: x] axis and translated [math: 7]\displaystyle {7} units in the negative direction of the [math: y] axis. The resulted function is [math: f(x)]=[input] Check Question 1
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