Choose the right option from each dropdown menu.

Jorge started a fresh R session and just clicked on a new R script file. He sees an Untitled1 R file on the top left pane, environment pane on the top right, console on the bottom left, and files/help pane on the the bottom right.

Jorge read a dataset into R from an RDS file and assigned it to df1. There were two columns and 6 rows in the data frame. Then, he typed the folowing code on Untitled1 R script and executed it:

library(tidyverse)

After that, tidyverse
[ Select ]
was
was not
displayed on Environment pane as a data frame.

df1 %% mutate(new = 1)

When Jorge typed above code on Untitled1 R script and executed it, the content of the resultant data frame
[ Select ]
was
was not
on Console.

Question

Choose the right option from each dropdown menu.

Jorge started a fresh R session and just clicked on a new R script file. He sees an Untitled1 R file on the top left pane, environment pane on the top right, console on the bottom left, and files/help pane on the the bottom right.

Jorge read a dataset into R from an RDS file and assigned it to df1. There were two columns and 6 rows in the data frame. Then, he typed the folowing code on Untitled1 R script and executed it:

library(tidyverse)

After that,  tidyverse 
[ Select ]
was
was not
 displayed on Environment pane as a data frame.

df1 %>% mutate(new = 1)

When Jorge typed above code on Untitled1 R script and executed it, the content of the resultant data frame 
[ Select ]
was
was not
   on Console.

BlackTom AI · Accepted Answer

Loading a package does not create a data.frame in your global environment, and simply evaluating an expression inside a script without printing or assigning it does not leave a persistent visible object. 1) Relevant knowledge points and concepts - RStudio Environment pane shows objects that exist in the current workspace (global environment), i.e., variables you have created or assigned. - library(tidyverse) loads the tidyverse package (and its constituent packages) but does not create a data.frame named tidyverse in your global environment. - Running a script with Source (or sourcing a file) executes code non-interactively; expressions that are not assigned or explicitly printed may execute but their results are not automatically shown in the Console. Running a single line interactively (Run line / Ctrl+Enter) will usually print results, but Source does not. 2) Step-by-step reasoning - Step 1: Jorge typed library(tidyverse) and executed it. That loads package code into the session, not a data object. The Environment pane therefore does not gain a data.frame called tidyverse. - Step 2: Jorge then ran df1 %>% mutate(new = 1) from the script. mutate returns a modified data.frame/tibble, but Jorge did not assign the result to a name (e.g., df2 <- df1 %>% mutate(...)). - Step 3: Because the expression was executed from the script (Untitled1) rather than interactively printed, the resultant tibble was not printed to the Console and no new object was stored in the Environment. 3) Intermediate steps / examples - If instead he did df2 <- df1 %>% mutate(new = 1) then df2 would appear in the Environment. - Or if he used print(df1 %>% mutate(new = 1)) or ran the line interactively, the console would show the result. 4) Why the correct answers are correct - “was not” for the Environment: library(tidyverse) does not create a data.frame named tidyverse in the global environment. - “was not” for the Console: the unassigned result evaluated from the script was not printed to Console when run via source/non-interactive execution. 5) Why the other options are incorrect - Choosing “was” for either part would claim that loading the package created a data.frame or that the script automatically printed the result; both contradict how R/RStudio handles package loading and non-assigned script evaluations. 6) Conclusion Therefore, tidyverse was not displayed in the Environment pane as a data frame, and the content of the resultant data frame was not displayed on the Console — matching the provided answers: “was not”, “was not”.

类似问题

na is a vector of numeric elements. You do not know how many elements na has. When you run the following, you are returned 1. sum(is.na(na)) If you execute the following, what would be the output? sum(is.na(na[which(is.na(na))] + na)) ==length(na)

Dharma has vector w in her active R session. There are no missing values in w. That is, there is no NA’s in w. She executed the following code: sum(w) == sum(w[which(w)]) R returned (outputted) TRUE on her R console. TRUE/FALSE: w is not a logical vector.

Suppose Jorge typed the following R code in a new R script and executed the entire code. x <- 2 y <- if_else(is.numeric(is.character(x)), 1, 2) y <- x/y What is the resulting value of y?

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