What is the result of the following code execution ?

x = input("x = ")
print(x+2)

Question

What is the result of the following code execution ?

x = input("x = ")
print(x+2)

BlackTom AI · Accepted Answer

input() in Python 3 returns a string, so x will be of type str; attempting to add an int to a str triggers a TypeError.

1) Relevant knowledge points and concepts
- input() in Python 3 always returns a string.
- The + operator is overloaded: for two strings it concatenates, for two numbers it adds; mixing str and int is not allowed and raises a TypeError at runtime.
- The code shown uses print(x+2) where x is a string and 2 is an int.

2) Step-by-step execution reasoning
- Step 1: Evaluate x = input("x = "). If the user types 2 and presses Enter, input() returns the string "2", so x == "2" (type str).
- Step 2: Evaluate x + 2. This attempts to add a str ("2") and an int (2).
- Step 3: Python checks operator compatibility and finds str + int is unsupported, so it raises a TypeError instead of producing a value.

3) Intermediate steps / illustration
- x = input("x = ")  -> x = "2"  (string)
- x + 2  -> "2" + 2  -> unsupported operation
- Result -> runtime exception: TypeError

4) Why the correct answer is correct
Because input() returned a string and Python does not implicitly convert that string to an integer for the + operator, the interpreter raises a TypeError when trying to add a string and an integer.

5) Why the other options are incorrect
- "2": would be printed if the code were print(x) and the user typed 2, but not for x+2.
- "2+2": is a literal string showing the expression, not the program output.
- "4": would be printed only if x were converted to an integer (e.g., x = int(input(...))) or if input returned an int; as given, x is a string so numeric addition does not occur.

6) Conclusion
Running this code in Python 3 produces a runtime TypeError, so the correct choice is: Execution TypeError.

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