Question textConsider the function f(x,y)=(2x2−y2)ex−2y.[math: f(x,y)=(2x2−y2)ex−2y.] The tangent plane to the graph of f[math: f] at the point (x,y)=(2,1)[math: (x,y)=(2,1)] is given by the formula z=a+bx+cy[math: z=a+bx+cy] where a=[math: a=]Answer 1 Question 6[input], b=[math: b=]Answer 2 Question 6[input] and c=[math: c=]Answer 3 Question 6[input]. At the (x,y)=(2,1)[math: (x,y)=(2,1)], the function is Answer 4 Question 6[select: , increasing, decreasing] in the direction of the vector (−3,2)[math: (−3,2)].多项填空题

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