What is the bond angle and geometry of the N2O molecule?[Fill in the blank]

Question

BlackTom AI · Accepted Answer

Because the central (middle) nitrogen is bonded to two atoms and has no lone pairs, N2O adopts a linear geometry with a 180° bond angle.

1) Relevant concepts
- Lewis structures, valence electron counting, and formal charges determine the best resonance structure.
- VSEPR: regions of electron density (bonding pairs + lone pairs) around the central atom determine molecular geometry; two regions → linear (180°).
- Hybridization: two regions → sp hybridization of the central atom.

2) Step-by-step reasoning and electron accounting
- Total valence electrons: N (5) + N (5) + O (6) = 16 electrons.
- Construct a connectivity N–N–O. Try a structure with a triple bond between the terminal N and the central N, and a single bond between the central N and O:
  - Bonds used: N≡N (3 pairs = 6 e−) and N–O (1 pair = 2 e−) → 8 electrons in bonds.
  - Remaining electrons: 16 − 8 = 8 e− → place as lone pairs to complete octets on terminal atoms.
  - Place one lone pair on left N (makes its octet), three lone pairs on O (makes its octet). Central N then has 4 bonding pairs (3 to left N, 1 to O) and no lone pairs.

3) Formal charges (intermediate steps)
- Left N: valence 5 − [nonbonding 2 + bonding/2 (6/2=3)] = 5 − 5 = 0.
- Central N: 5 − [nonbonding 0 + bonding/2 (8/2=4)] = 5 − 4 = +1.
- O: 6 − [nonbonding 6 + bonding/2 (2/2=1)] = 6 − 7 = −1.
This resonance (N≡N–O with +1 on central N and −1 on O) is a major contributor. Alternative resonance forms still leave the central N with two regions of electron density.

4) Why the correct answer is correct
- Central N has exactly two electron domains (two sigma bonds) and no lone pairs → VSEPR predicts linear arrangement, bond angle 180°. Central atom is sp hybridized.

5) Why other options are incorrect
- Options a/b/c (120° trigonal planar/tripodal/bent) require three regions of electron density or an asymmetric lone-pair arrangement on the central atom. N2O’s central N does not have three regions or a lone pair that would produce a 120° geometry or a bent shape.

6) Conclusion
- The bond angle and geometry of N2O are 180° and linear; therefore the correct choice is d. 180o and linear.

What is the bond angle and geometry of the N2O molecule?[Fill in the blank]单项选择题

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