How many moles of HCl are there in 10 mL of a solution with a concentration of 0.5 mol/L?

Question

BlackTom AI · Accepted Answer

First, restate the problem in my own words: You have a solution with a concentration of 0.5 M (0.5 moles per liter) and a volume of 10 mL, and you want to know how many moles of HCl are present.

Option a: 0.005 mol. To obtain moles from concentration and volume, use n = C × V. Here C = 0.5 mol/L and V = 10 mL = 0.01 L. Multiplying gives n = 0.5 × 0.01 = 0.005 mol. This matches the calculated amount, so this option reflects the correct calculation in SI units.

Option b: 5 mol. This would require a much larger amount of solution or a much higher concentration. For example, 0.5 mol/L × 10 L would give 5 mol. Since the volume here is only 0.01 L, obtaining 5 mol would be incorrect, indicating a mismatch between volume and concentration.

Option c: 0.5 mol. This would correspond to having 1 L of a 0.5 M solution, since 0.5 mol/L × 1 L = 0.5 mol. The given volume is 0.01 L, not 1 L, so this value arises from an incorrect volume assumption.

Option d: 0.05 mol. This would come from 0.5 mol/L × 0.1 L = 0.05 mol. The calculation would be valid if the volume were 100 mL (0.1 L), but the problem states 10 mL, so this is a volume-area misapplication.

In summary, the key steps are to convert the volume to liters and apply n = C × V. The only choice that aligns with 0.5 mol/L × 0.01 L is 0.005 mol, while the other options reflect common unit or arithmetic slips stemming from incorrect volume assumptions or misapplied formulas.

How many moles of HCl are there in 10 mL of a solution with a concentration of 0.5 mol/L?单项选择题

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