var i = 28;
if ( i / 2 % 2 0 ) {
document.write("The number is an odd integer");
}
else {
document.write("The number is an even integer");
}
What is displayed when the code segment above is executed?

Question

var i = 28;
if ( i / 2  % 2 > 0 ) {
  document.write("The number is an odd integer");
}
else {
  document.write("The number is an even integer");
}
What is displayed when the code segment above is executed?

BlackTom AI · Accepted Answer

Compute i / 2 % 2 for i = 28: JavaScript evaluates the expression (i / 2) % 2 because the operators / and % have the same precedence and are evaluated left to right.

1) Relevant knowledge points and concepts
- Operator precedence and associativity: / and % are same-precedence arithmetic operators and are evaluated left-to-right.
- / in JavaScript produces a Number (floating-point if needed); with integer operands it yields the exact integer value when divisible.
- % returns the remainder after division.
- The if condition tests whether the computed value is greater than 0; if true the first branch runs, otherwise the else branch runs.
- document.write outputs the provided string to the page (no runtime error here).

2) Step-by-step reasoning with intermediate steps
- Start with i = 28.
- Evaluate i / 2 first: 28 / 2 = 14.
- Next evaluate (result) % 2: 14 % 2 = 0 (14 divided by 2 leaves remainder 0).
- Now evaluate the comparison: 0 > 0 is false.

3) Why that leads to the else branch
- Because the condition (i / 2 % 2 > 0) is false, the else block executes, calling document.write("The number is an even integer").

4) Why the correct answer is correct
- The computed remainder is zero, indicating that i/2 is even, so the else string "The number is an even integer." is printed.

5) Why the other options are incorrect
- "Nothing is printed. The result of the computation is equal to 0." is wrong because although the expression equals 0, the else branch still prints text.
- "Nothing is printed. There is a runtime error." is wrong because no runtime error occurs; document.write is valid and the code runs.
- "The number is an odd integer." is wrong because the condition for that branch (remainder > 0) is false for i = 28.

Conclusion: The output is "The number is an even integer." which matches the provided correct answer.

var i = 28; if ( i / 2 % 2 > 0 ) { document.write("The number is an odd integer"); } else { document.write("The number is an even integer"); } What is displayed when the code segment above is executed?单项选择题

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