The 200 mm conductor carrying 3 A has a flux density of 600 At/m, the force exerted on it is:

Question

The 200 mm  conductor carrying 3 A has a flux density of 600 At/m, the force exerted on it is:

BlackTom AI · Accepted Answer

Magnetic force on a current-carrying conductor is given by F = B I L (for the conductor perpendicular to the magnetic field, sinθ = 1).

1) Relevant concepts
- B is magnetic flux density (Tesla, Wb/m^2).
- I is current (A).
- L is conductor length in meters.
- The magnitude of the Lorentz force on a straight conductor of length L in a uniform B-field perpendicular to the conductor is F = B I L.

2) Step-by-step reasoning and calculations
- Convert length: 200 mm = 0.200 m.
- Use given quantities: I = 3 A, B (flux density) = 600 (question label “600 At/m” is taken here as the numeric flux density value 600 in consistent units).
- Apply formula: F = B I L.
- Substitute values: F = 600 × 3 × 0.200.

3) Intermediate arithmetic
- 3 × 0.200 = 0.600.
- 600 × 0.600 = 360.0.

4) Why this answer is correct
- The computation follows directly from F = BIL with the conductor perpendicular to the magnetic field, giving F = 360 N. This matches the numerical result obtained by plugging the provided B, I, and L values into the standard formula.

5) Why the other multiple-choice options are incorrect
- If F were 63 N, the implied B would be 63/(3×0.2) = 105 (in the same numeric units) — not the given 600.
- If F were 36 N, implied B = 36/(3×0.2) = 60 — again not 600.
- If F were 630 N, implied B = 630/(3×0.2) = 1050 — not 600.
Each of those would require a different flux density than the one stated.

6) Conclusion
Using F = BIL with L = 0.2 m, I = 3 A and B = 600 yields F = 360 N. This confirms the correct choice is 360 N.

The 200 mm conductor carrying 3 A has a flux density of 600 At/m, the force exerted on it is: 单项选择题

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