In a liquid-liquid separation using water and ethyl acetate, ethyl acetate will be the top layer.

Question

BlackTom AI · Accepted Answer

Ethyl acetate has a lower density than water, so it occupies the upper layer in a separatory funnel.

Relevant knowledge points:
- Immiscible liquids separate into layers according to their densities: the less dense liquid forms the top layer, the denser liquid the bottom.
- Typical densities at lab temperature: water ≈ 1.00 g/mL; ethyl acetate ≈ 0.90–0.91 g/mL.
- Solubility/polarity affects miscibility but not the ordering of layers once two phases exist.

Step-by-step reasoning:
1. Identify that water and ethyl acetate are largely immiscible under normal laboratory conditions (ethyl acetate is moderately soluble in water but enough to form two phases).
2. Look up or recall densities: water ≈ 1.00 g/mL; ethyl acetate ≈ 0.902 g/mL.
3. Compare densities: 0.902 g/mL (ethyl acetate) < 1.00 g/mL (water). The difference is about 0.098 g/mL.
4. By the principle that the less dense liquid floats on the denser liquid, ethyl acetate will sit above the aqueous layer.

Why the correct answer is correct:
Because ethyl acetate is less dense than water, it will float and form the top layer in a liquid–liquid separation using a separatory funnel at typical lab temperatures. This is a direct consequence of density differences.

Why “False” would be incorrect:
Answering “False” would assert that ethyl acetate is the bottom layer, which contradicts the measured densities. Only solvents denser than water (e.g., dichloromethane, density ≈ 1.33 g/mL) form the bottom layer.

Note on caveats: Emulsions or temperature extremes can temporarily disrupt layering, but under normal conditions ethyl acetate is the top layer.

Conclusion: The statement is True, which matches the provided answer.

In a liquid-liquid separation using water and ethyl acetate, ethyl acetate will be the top layer.判断题

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