SLL: Insertion At Head Give the statements to implement an insertion at the head of a linked list as shown below. class Node { private Node next; private T data; Node(T data) { this.data = data; } Node getNext() { return next; } T getData() { return data; } } public void insertAtHead(T data) { Node node = new Node (data); // A: statement to achieve action A in the picture below // B: statement to achieve action B in the picture below ... } 1: A 2: B

Link the new node to the existing list, then move the head pointer to the new node: node.next = head; followed by head = node ; 1) Relevant concepts - A singly linked list is represented by Node objects that hold data and a next pointer. - The head variable references the first node of the list. - To insert at the head you must (a) make the new node point to the current first node and (b) update head to reference the new node. Order matters to avoid losing the original list. 2) Step-by-step reasoning - After Node node = new Node (data); the new node exists but its next is currently null. - Action A (link the new node into the list): set node.next = head; This makes the new node’s next pointer refer to the current first node, preserving the existing list that follows head. - Action B (update the head pointer): set head = node ; This updates the list’s head so the newly inserted node becomes the first node. 3) Intermediate-state explanation - Before any statements: new node -> null; head -> oldFirst -> ... - After node.next = head; new node -> oldFirst -> ... - After head = node ; head -> new node -> oldFirst -> ... 4) Why the chosen statements are correct - node.next = head maintains the link to the old list so we don’t lose it. - head = node makes the newly linked node the list’s first element. 5) Why other options are incorrect (brief) - head.next = node; attaches the new node after the current head instead of making it the head. - node = head; merely reassigns the local variable node to point at head, discarding the newly created node. - head.next = head; creates a self-loop at the head (incorrect structure). - node.next = node; creates a self-loop in the new node (isolated cycle). Conclusion: therefore A = "node.next = head;" and B = "head = node ;", which matches the provided answer.

SLL: Insertion At Head Give the statements to implement an insertion at the head of a linked list as shown below. class Node<T> { private Node<T> next; private T data; Node(T data) { this.data = data; } Node<T> getNext() { return next; } T getData() { return data; } } public void insertAtHead(T data) { Node<T> node = new Node<T>(data); // A: statement to achieve action A in the picture below // B: statement to achieve action B in the picture below ... } 1: A 2: B匹配题

head.next = node;

head = node ;

node = head;

head.next = head;

node.next = node;

node.next = head;

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类似问题

SLL-InsertAfter Which XXX completes the following algorithm for inserting a new node into a singly-linked list? ListInsertAfter(list, curNode, newNode) { if (list⇢head == null) { list⇢head = newNode list⇢tail = newNode } else if (curNode == list⇢tail) { list⇢tail⇢next = newNode list⇢tail = newNode } else { XXX } } -- a.newNode⇢next = curNode⇢next; curNode⇢next = null; --- b.newNode⇢next = null; curNode⇢next = list⇢tail⇢next; --- c.newNode⇢next = curNode⇢next; curNode⇢next = newNode; --- d.newNode⇢next = curNode⇢next; curNode = newNode;

LinkedList (insertAt) Consider the following LinkedList class and Code Snippet. The method insertAt(int toInsert, int local) creates a new node containing the data toInsert and inserts it into the linked list in the correct location. If an element already exists at that index, the remaining part of the LinkedList is shifted to the right to make room for the new element. Suppose my initial LinkedList is as follows public class LinkedListInt { private static class Node{ int data; Node next; public Node(int data,Node next) { this.data = data; this.next = next; } } private Node head; private Node tail; public void insertAt(int toInsert, int local) { int count = 0; Node current = head; while(current!=null) { if(count==local-1) { Node n = new Node(toInsert,current.next); current.next = n; return; } current = current.next; count++; } }} What does the linked list look like after the call insertAt(5,1)? Answer: [Fill in the blank] (in the format of x,x,x, ... ,x without any spaces.) Using the original LinkedList {2,3,5,7}, after the call insertAt(1,4) what does the linked list look like ? Answer: [Fill in the blank] (in the format of x,x,x, ... ,x without any spaces.) what is the value of the tail instance variable ? Answer: [Fill in the blank] (a number) (y/n) Is the tail instance variable updated correctly? [Fill in the blank] (fill in y or n) Using the original LinkedList, what does the linked list look like after I call insertAt(6,0)? (y/n) List is unchanged. The new value 6 is never inserted. [Fill in the blank] Using the original LinkedList {2,3,5,7}, what does the linked list look like after I call insertAt(9,7)? Answer: [Fill in the blank] (in the format of x,x,x, ... ,x without any spaces.)

Insertion At Head: Corner Case Consider the implementation of the method InsertAtHead() of the class LinkedList. Fill in the blanks. Vanilla case. Corner Case where the list is empty before insertion. After insertion public class LinkedList<T> { private Node<T> head; private Node<T> tail; public void insertAtHead(T data) {…} public void appendAtTail(T data) {…} public int size() {…} public void delete(T data) {…} class Node {…} } public void insertAtHead(T data) { Node<T> node = new Node<T>(data); _A_; // vanilla case _B_; // vanilla case if (_C_) // corner case where the list is empty _D_ // } 1: _A_ 2: _B_ 3: _C_ 4: _D_

What is the correct way to insert a new node x at the beginning of a linked list?

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What is the correct way to insert a new node x at the beginning of a linked list?

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Complete the correct code for inserting a node in a list. InsertAfter(IntNode* nodeLoc) { IntNode* tmpNext = nullptr; XXX }

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