Let's evaluate the following limit: lim 𝑥 → 1 sin ⁡ ( 𝜋 𝑥 ) 𝑥 − 1   Can l'Hopital's rule be used to evaluate the limit? [ Select ] Yes No This limit is an indeterminate form of type [ Select ] infinity/infinity 0/0 It's not an indeterminate form 0^0 1^infinity infinity - infinity . The final answer is [ Select ] -pi pi/2 -1 0 pi 1 . 多重下拉选择题

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