We can pass objects as method arguments in Java

Question

BlackTom AI · Accepted Answer

Objects in Java are passed as references by value: when you pass an object to a method you pass a copy of the reference to that object, not the object itself and not a direct alias to the caller’s variable.

Relevant knowledge points and concepts
- Java parameter passing is always pass-by-value. For primitives, the actual value is copied. For objects, the value copied is the reference (pointer) to the object.
- The method receives its own copy of the reference. Both caller and callee references point to the same heap object initially.
- Because both references target the same object, the method can mutate the object's state (fields). Reassigning the parameter to a new object inside the method does not change the caller’s reference.

Step-by-step reasoning with an example
1. Create object: MyObj a = new MyObj(); a.field = 1;
2. Call method: modify(a);
   - At call time, the value of reference a (say address 0x100) is copied into the parameter variable inside modify (param = 0x100).
3. Inside method: param.field = 2;
   - Both a and param point to same object at 0x100, so the mutation is visible to the caller; a.field becomes 2.
4. If method does param = new MyObj(); param.field = 3;
   - This reassigns only the local copy param; a in caller still references original object. Caller does not see param reassignment.

Why the correct answer is correct
- You can indeed pass objects as method arguments in Java; the method can modify the object's internal state and those changes are observable by the caller because the reference (pointer) to the same object was passed (by value).

Why "False" is incorrect
- Saying “False” would deny that objects can be passed as arguments, which is wrong: object references are passed and used routinely. The confusion usually arises from misunderstanding pass-by-value vs pass-by-reference.

Conclusion
This confirms the correct answer is True.

We can pass objects as method arguments in Java判断题

类似问题

Select the correct output. class Person { String name; int age; public static void main(String[] args) { Person p = new Person(); p.name = "Trina"; updatePerson(p); System.out.printf("%s, %d", p.name, p.age); } private static void updatePerson(Person p){ p = new Person(); p.age = 1; } }

For this specific pattern, the appropriate technique at CV12 (Zhongwan) should be:

Which prescription is MOST appropriate for this case

What is the most appropriate treatment principle based on the case?

Select the correct method that can overload the following method. public int addKey(String s, int i);

The result of dividing by 0 in Java is a ___________ ?

更多留学生实用工具

智能学习助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单