Which intermolecular interactions contribute most to the water solubility of organic compounds? A. ionic interactions and dispersion forces B. hydrogen bonding and ion-dipole interactions C. dispersion forces and hydrogen bonding D. dipole-dipole interactions and dispersion forces

Question

BlackTom AI · Accepted Answer

Hydrogen bonding and ion–dipole interactions dominate because liquid water is highly polar and can both donate/accept hydrogen bonds and strongly solvate ions.

1) Relevant knowledge points and concepts
- Water is polar (large dipole) and forms strong hydrogen bonds (H···O) with solute functional groups that have H-bond donors (–OH, –NH) or acceptors (C=O, –O–). Typical H‑bond energies are on the order of several to a few tens of kJ·mol–1, making them energetically favorable for dissolution.
- Ion–dipole interactions occur when ions (charged species, e.g., RCOO– or RNH3+) are stabilized by the electric field of polar water molecules; these interactions are often stronger than neutral dipole–dipole contacts and drive dissolution of ionic/ionizable organic compounds.
- Dispersion (London) forces are weak, nonpolar interactions that favor solubility in nonpolar solvents and become relatively less important in water. Dipole–dipole interactions are intermediate in strength but still weaker than H‑bonding and ion–dipole for aqueous solvation.

2) Step‑by‑step reasoning
- Water solvates polar/ionizable solutes most effectively when it can form specific, strong interactions: hydrogen bonds with polar functional groups, and ion–dipole interactions with charged species.
- For a neutral polar molecule (e.g., ethanol), hydrogen bonding to water lowers the free energy of mixing and increases solubility.
- For ionizable organics (e.g., carboxylic acids, amines), ionization produces ions that are strongly stabilized by ion–dipole hydration, greatly increasing solubility compared to the neutral form.
- Nonpolar hydrocarbons rely primarily on dispersion forces and are poorly soluble in water because forming water–water hydrogen bonds around a hydrophobic solute is entropically and energetically unfavorable.

3) Calculations/intermediate steps
- No numerical calculation required, but relative strength ordering: ion–dipole ≳ hydrogen bonding > dipole–dipole > dispersion (for aqueous solvation relevance).

4) Why the correct answer is correct
- Option B (hydrogen bonding and ion–dipole interactions) names the two specific interactions that most directly stabilize organic solutes in water: H‑bonding for polar neutral functional groups and ion–dipole for charged/ionized species. These provide the strongest energetic drivers for aqueous solubility.

5) Why other options are incorrect
- A (ionic interactions and dispersion forces): “Ionic interactions” between ions of the solute (ion–ion) are not what promotes solubility; ions must be hydrated via ion–dipole interactions. Dispersion forces favor solubility in nonpolar solvents, not water.
- C (dispersion forces and hydrogen bonding): while hydrogen bonding helps, dispersion forces are weak and often reduce water solubility (hydrocarbons are insoluble).
- D (dipole–dipole interactions and dispersion forces): dipole–dipole is weaker than H‑bonding/ion–dipole, and dispersion is unfavorable for aqueous solubility.

6) Conclusion
Hydrogen bonding and ion–dipole interactions are the principal contributors to water solubility of organic compounds; therefore the correct answer is B (matches the provided answer).

Which intermolecular interactions contribute most to the water solubility of organic compounds? A. ionic interactions and dispersion forces B. hydrogen bonding and ion-dipole interactions C. dispersion forces and hydrogen bonding D. dipole-dipole interactions and dispersion forces单项选择题

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