A constant-volume gas thermometer is used to measure the temperature of an object. When the thermometer is in contact with water at its triple point (273.16K) the pressure in the thermometer is 8.500 × 104 Pa.

When it is in contact with the object the pressure is 9.650 × 104 Pa. The temperature of the object is:

Question

A constant-volume gas thermometer is used to measure the temperature of an object. When the thermometer is in contact with water at its triple point (273.16K) the pressure in the thermometer is 8.500 × 104 Pa.

When it is in contact with the object the pressure is 9.650 × 104 Pa. The temperature of the object is:

BlackTom AI · Accepted Answer

The problem describes a constant-volume gas thermometer, where pressure is proportional to temperature at fixed volume (P ∝ T).

First, identify the known point from the triple point of water: T1 = 273.16 K corresponds to P1 = 8.500 × 10^4 Pa.

Next, note the pressure when in contact with the object: P2 = 9.650 × 10^4 Pa. Since V is constant, the temperature T2 scales with pressure according to T2 = T1 × (P2 / P1).

Compute the pressure ratio: P2 / P1 = (9.650 × 10^4) / (8.500 × 10^4) = 9.650 / 8.500 ≈ 1.1353.

Now multiply by T1 to obtain T2: T2 ≈ 273.16 K × 1.1353 ≈ 310 K (approximately).

Therefore, the temperature of the object, as measured by the constant-volume gas thermometer, is about 310 Kelvin.

If you want the precise value, multiply 273.16 by 9.650/8.500 to get T2 ≈ 310.2 K, which rounds to 310 K in the given context.

类似问题

What happens to the pressure of a gas inside a container if the temperature of the gas decreases?

What happens to the temperature of a gas when it is compressed?

If a sealed syringe is heated, in which direction will the syringe plunger move?

If a sealed syringe is plunged into cold water, in which direction will the syringe piston slide?

As the temperature of a fixed volume of a gas increases, the pressure will ____.

更多留学生实用工具

智能学习助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单