Pick the code/s that correctly implements the following: Get a user input and save as 'min' variable if this input is not an integer, go to step 1
print it out to the console and exit the loop

Question

BlackTom AI · Accepted Answer

Using a guarded int() conversion inside a repeating loop ensures the input is accepted only when it can be parsed as an integer; otherwise the loop repeats.

Relevant concepts
- input() always returns a string.
- int(s) converts a numeric string to integer and raises ValueError if s is not an integer representation.
- Use while True with break to repeat until valid and then exit.
- try/except catches ValueError from int() and lets the loop repeat.

Step-by-step reasoning for option a
1. Loop: while True.
2. Inside try: min = int(input("Enter min value ")) attempts to convert the typed string to int.
3. If conversion succeeds, print(min) executes and break exits the loop.
4. If conversion fails, a ValueError is raised and caught by except ValueError: pass, which does nothing and the loop repeats.
This exactly implements: ask, if not integer repeat, otherwise print and exit.

Step-by-step reasoning for option e
1. Loop: while True.
2. Read raw input into min as a string: min = input(...).
3. Inside try: attempt int(min). If conversion succeeds, the code assigns min = int(min), prints min and break exits the loop.
4. If conversion fails, int(min) raises ValueError, caught by except ValueError: pass, and the loop repeats.
(The shown e-code also tests int(min) % 1 == 0 which is redundant but does not break correctness; successful conversion leads to printing and breaking, failures cause repeat.)

Why the other options are incorrect (brief)
- b: Compares the string min to int(min) (different types) so equality is always False; the code will not print on successful conversion. It may also rely on exceptions inconsistently.
- c: Uses "if min is int" which tests object identity (string is not the int type), so condition is always False and valid integers are never accepted.
- d: Appears to convert inside try but handles the wrong branch: it prints and breaks in except (i.e., when conversion failed) — the opposite behavior of the requirement.

Conclusion
Options a and e correctly implement the required behavior, so the correct answers are: a. and e., matching the provided answer.

Pick the code/s that correctly implements the following: Get a user input and save as 'min' variable if this input is not an integer, go to step 1 print it out to the console and exit the loop多项选择题

类似问题

Which keyword handles a thrown exception?

Which keyword explicitly throws an exception?

Error handler codes, to handle unusual errors are:

What does the finally block do?

How do you raise a custom exception?

For the following code: What will the value be for istr after this code executes?

What happens when a raise statement is encountered in a function?

What happens if an exception occurs and there is no matching catch block, but a finally block exists?

更多留学生实用工具

智能学习助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单