Compared to a visible light photon, an ultraviolet light photon has...

Question

BlackTom AI · Accepted Answer

Consider the core relationships governing photons: energy is proportional to frequency (E = hν) and inversely proportional to wavelength (ν = c/λ). With that in mind, let's evaluate each option.

Option 1: 'Higher energy, lower frequency, shorter wavelength.' This mixes two true-seeming ideas (shorter wavelength implies higher energy) with a contradictory one (lower frequency). Since energy increases with frequency, having lower frequency would not yield higher energy, so this combination is inconsistent with photon physics.

Option 2: 'Lower energy, lower frequency, longer wavelength.' All three aspects are aligned in the wrong direction relative to ultraviolet photons: lower energy and lower frequency correspond to longer wavelengths, not the UV regime. This option describes infrared or red-light characteristics, not UV.

Option 3: 'Lower energy, higher frequency, longer wavelength.' Here, the frequency and wavelength relationship violates the fundamental inverse link between wavelength and frequency (ν and λ are inversely related). A higher frequency should correspond to a shorter wavelength, and the stated longer wavelength with higher frequency is physically impossible for a single photon.

Option 4: 'Higher energy, higher frequency, shorter wavelength.' This statement matches the well-established photon relationships: higher frequency means higher energy (E = hν), and higher frequency implies shorter wavelength (λ = c/ν). Since ultraviolet photons sit at higher frequencies than visible photons, they indeed have higher energy and shorter wavelength than visible light.

In summary, the only option that consistently aligns with E = hν and ν = c/λ across all three descriptors is the one that lists higher energy, higher frequency, and shorter wavelength. The other options violate either the energy–frequency linkage or the inverse relationship between frequency and wavelength, leading to internal contradictions about UV photons.

Compared to a visible light photon, an ultraviolet light photon has...单项选择题

类似问题

Which of the following is not part of the electromagnetic spectrum.

The human eye can detect Gamma rays.

Which of the following are detectable by the human body?

Which series goes from least energetic to most (with relation to electromagnetic waves)?

Chose the answer that lists the electromagnetic wave radiant energy forms in order, from longest wavelength to shortest, from lowest frequency to highest.

Match the type of non-visible radiation to the description of how we interact with it in our daily lives. 1: Infrared 2: Ultraviolet 3: Microwave 4: X-ray 5: Radio

Rank the types of radiation below in order of short wavelength (1) to long wavelength (5). 1: Infrared 2: Ultraviolet 3: Radio 4: X-ray 5: Visible

Rank the following electromagnetic radiations in order of increasing wavelength: 1: 1 (shortest wavelength) 2: 2 3: 3 4: 4 5: 5 6: 6 7: 7 (longest wavelength)

更多留学生实用工具

智能学习助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单