There are 2
points near a positive point charge Point 1 and Point 2. 1) Find the ratio (E1/E2) of electric field strength?

Question

BlackTom AI · Accepted Answer

We start by recalling the basic relation for the electric field due to a point charge: E = kq / r^2, where r is the distance from the charge." +
  "

To compare E1 and E2 at two locations Point 1 and Point 2, we use the inverse-square dependence: E1 / E2 = (r2^2) / (r1^2)." +
  "

From the diagram, Point 2 lies farther from the charge than Point 1. If the distances are such that r2 = 3 r1 (i.e., Point 2 is three times as far away as Point 1), then" +
  "
E1 / E2 = (r2^2) / (r1^2) = (3 r1)^2 / (r1^2) = 9." +
  "

Interpretation note: the key step is recognizing the r^2 dependence of the field magnitude and substituting the correct distance ratio between the two points. If the actual distance ratio were different, the ratio E1 / E2 would change accordingly, since it scales with the square of the distance ratio." +
  "

Since the problem involves a single positive point charge and two locations at known relative distances, the ratio is determined entirely by how much farther Point 2 is compared to Point 1.

There are 2 points near a positive point charge Point 1 and Point 2. 1) Find the ratio (E1/E2) of electric field strength?数值题

类似问题

The potential difference between the plates of a parallel plate capacitor with the plate separation of 6 cm is 60 V. What is the electric field between the plates of this capacitor?

Calculate the electric field strength when a force of 4.0 × 10-9 𝑁 acts on a charge of 8.5 × 10-6𝐶.

Which, among the following is the correct expression for an electric field?

An electric field is:

The potential at x = 8 m is -2000 V and at x = 2 m is +400 V. What is the magnitude and direction of the electric field?

Two point charges are placed along a horizontal axis with the following values and positions: +3.0 µC at x = 0 cm and -6.0 µC at x = 20 cm. At what point along the x axis is the electric field zero?

The average distance of the electron from the proton in the hydrogen atom is 0.51 x 10-10 m. What is the electric field from the proton’s charge at the location of the electron? (ke = 8.99 x 109 N×m2/C2, elementary charge e = 1.6 x 10-19 C)

Consider the following diagram. Two parallel plates are separated in vacuum by 0.200 m. The top plate has a potential of 400 V and the bottom plate has a potential of −600 V. An alpha particle is released from the top plate.The acceleration of the alpha particle between the plates is

更多留学生实用工具

智能学习助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单