The boiling points of six consecutive elements in the Periodic Table are tabulated below. [table]
Element | A | B | C | D | E | F Boiling point (oC) | + 613 | + 685 | + 58 | - 152 | + 688 | + 770
[/table]It is correct to state that:

Question

BlackTom AI · Accepted Answer

Boiling points of known elements give clear identification: +58 °C matches bromine (Br2, boiling point ≈ 58.8 °C) and −152 °C closely matches krypton (bp ≈ −153 °C). Recognizing a sequence of six consecutive elements across the periodic table therefore lets us place the others by proximity: A (≈ +613 °C) corresponds to arsenic (As), B (≈ +685 °C) to selenium (Se), C to bromine (Br2), D to krypton (Kr), and E (≈ +688 °C) to rubidium (Rb). The central knowledge points are (1) many elements have characteristic boiling points that identify them, (2) halogens (like bromine) are diatomic in their elemental molecular form (Br2), and (3) metallic elements have much higher boiling points than molecular or noble-gas elements.

Step-by-step reasoning:
1. Compare each given boiling point with standard values: +58 °C → bromine (Br2); −152 °C → krypton (noble gas). The adjacent high boiling points around +600–+700 °C match known metallic/metalloid elements (As, Se, Rb) that flank Br and Kr in the periodic table. This confirms these six are consecutive elements in order As (A), Se (B), Br (C), Kr (D), Rb (E), and the next metal (F).
2. Bromine (element C) in its elemental form exists as diatomic molecules Br2; that is a fundamental chemical property of the halogen group (all diatomic: F2, Cl2, Br2, I2).
3. Therefore the statement that “element C exists in nature as diatomic molecules C2” (meaning C2 as the diatomic form of element C) is correct—interpreting “C2” to mean the diatomic form of element C (Br2).

Why the other choices are incorrect:
- A: “element F does not form compounds with any other element.” High-boiling elements in this region are metals and readily form compounds; inertness is characteristic of noble gases, not these metals—so A is false.
- B: “elements C and D form a compound CD.” C is a halogen and D is a noble gas; stable binary compounds of a halogen with a noble gas are not generally formed under normal conditions (and Kr–Br compounds are not known), so B is not generally true.
- C: “elements A and F form A2F.” No simple reason (valence or periodic trends) supports that specific stoichiometry; metals and metalloids typically form other types of compounds, so C is not a justified general statement.
- E: “element A has more metallic properties than element E.” A (As) is a metalloid while E (Rb) is an alkali metal; E is more metallic, so E is false.

Conclusion: Identifying C as bromine and using the halogen property that it is diatomic confirms the correct choice is D, matching the provided answer.

The boiling points of six consecutive elements in the Periodic Table are tabulated below. [table] Element | A | B | C | D | E | F Boiling point (oC) | + 613 | + 685 | + 58 | - 152 | + 688 | + 770 [/table]It is correct to state that:单项选择题

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