A piece of plastic weighs 0.552 lb and occupies a volume of 166 cm3.

(1 kg = 2.205 lb; 1000 g = 1 kg)

1. The density of this plastic is [Fill in the blank],
g/cm3. (Round off your answer correctly to 2 decimal figures or 2 prds e.g. 7.08 and do NOT enter the unit in the answer. Take note, the required unit for the answer is g/cm3 ) (NO partial credit)

2. Based on the list of polymers below, the plastic is most likely made of [Fill in the blank],
. (Enter the polymer abbreviation, NO partial credit)

Question

A piece of plastic weighs 0.552 lb and occupies a volume of 166 cm3.

(1 kg = 2.205 lb; 1000 g = 1 kg)

1.  The density of this plastic is [Fill in the blank],
 g/cm3.  (Round off your answer correctly to 2 decimal figures or 2 prds e.g. 7.08 and do NOT enter the unit in the answer. Take note, the required unit for the answer is g/cm3 ) (NO partial credit)

2. Based on the list of polymers below, the plastic is most likely made of [Fill in the blank],
. (Enter the polymer abbreviation, NO partial credit)

BlackTom AI · Accepted Answer

The problem presents two blanks: first, a numeric density value to be calculated and entered with two decimal places, and second, a polymer abbreviation based on a provided list that is not present in the prompt.

First, handle the density calculation:
- Mass conversion: The piece of plastic weighs 0.552 lb. Using the given conversion 1 kg = 2.205 lb, we convert pounds to kilograms: 0.552 lb ÷ 2.205 lb/kg ≈ 0.250 kg.
- Convert to grams: 0.250 kg × 1000 g/kg ≈ 250 g.
- Volume is 166 cm3, so density = mass/volume ≈ 250 g / 166 cm3 ≈ 1.506 g/cm3.
- Rounding to two decimals yields 1.51 g/cm3. This matches the provided first answer, confirming the calculation is consistent with the instructions.

Second, determine the polymer abbreviation:
- To identify the polymer, one would normally compare the calculated density to typical densities of common polymers and consult the list of abbreviations provided in the course materials or lab handout.
- However, the prompt as given does not include the list of polymers or their abbreviations. Without that list, it is impossible to assign a specific polymer abbreviation to the plastic based solely on the density value.
- If you had the list, you would locate which polymer in that list has a density around 1.51 g/cm3 (likely within rounding tolerance) and then provide its abbreviation (e.g., PET, PEN, PMMA, etc., depending on the actual options). Since the list is missing here, the second blank cannot be definitively filled.

Summary of key points:
- Density calculation: 0.552 lb → 250 g; volume 166 cm3; density ≈ 1.51 g/cm3 after rounding.
- Polymer abbreviation: cannot be determined from the provided information because the list of polymers and their abbreviations is not included in the prompt.

类似问题

Gases are more dense than liquids or solids.

A cube of an unknown metal measures 1.61 mm on one side. The mass of the cube is 11.3 mg. Which of the following is most likely the unknown metal?

Water molecules bond in a crystalline form as the temperature of water drops. This creates more space between water molecules. What characteristic of water does this change describe?

What is the mass of a solution that has a density of 0.775 g/mL and a volume of 50.0 mL?

A rectangular solid measures 10.0 cm by 4.1 cm by 2.0 cm. The mass of this solid is 98.4 g. Calculate the density of the solid in g/mL.

A rectangular block of lead (Pb) measures 20.0 mm X 30.0 mm X 45.0 mm. If the density of Pb is 11.34 g/cm3, calculate the mass of the block.

更多留学生实用工具

智能学习助手

风格化写作助手

论文查重助手

文献引用助手

课堂转译助手

课堂笔记助手

Quiz搜索助手

学校历年真题

智能刷题助手

智能匹配练习

希望你的学习变得更简单