Consider the following code: a = 4 # Line 1 if a == 4: # Line 2 print("B") # Line 3 print("C") #Line 4 Which lines are run, and in what order?单项选择题
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Question at position 15 What will be the output of the program after the following code fragment is executed? [table] 1 def check_temperature(temp: int):2 if temp <= 0:3 return 'Freezing!'4 elif temp < 45:5 return 'Warm!'6 else:7 return 'Boiling!'8 9 print(check_temperature(0))10 print(check_temperature(100))11 print(check_temperature(45)) [/table] Which of the following options is the correct missing code? Freezing!Boiling!Boiling!Freezing!Boiling!Warm!Freezing!Warm!Boiling!Warm!Boiling!Boiling!Clear my selection
Question at position 7 If the missing lines are filled in correctly, the program should continuously take a number from the user and add it to a total until they enter a negative number, where the program will end and output the total of all previous numbers. Negative numbers should NOT be included in the total. Below is an example output of the program, where bolded text is input to the program: Enter a number: 3Enter a number: 7Enter a number: -2Total: 10 [table] 1 total = 02 keep_adding = True3 4 while keep_adding:5 number = int(input('Enter a number: '))6 if number # ( code WILL go here ) 0:7 # ( code WILL go inside IF )8 else:9 # ( code WILL go inside ELSE )10 print('Total:', total) [/table] Which of the following options is the correct missing code? (Code filled in has been bolded.)6 if number > 0:7 keep_adding = True8 else:9 total = total + number6 if number < 0:7 total = total + number8 else:9 keep_adding = False6 if number < 0:7 keep_adding = False8 else:9 total = total + number6 if number <= 0:7 total = total + number8 else:9 keep_adding = TrueClear my selection
Q17. Why is the order of conditions important in an if–elif–else statement?
In the below code, what is the value stored in `k` after the code is executed? public class Q { public static void main(String[] args) { int k = -1; int t = 5; int y = 9; int r; if (t + y > 13) { r = 17; } else { r = t + 1; t += 3; k = r + 5; } k += r; } }
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