If the flow from a catchment is 10m3/s for 3 hours and the total rainfall depth is 10.8 mm, what is the catchment area (in ha)? Hint: remember one hectare = 10000m2

Question

BlackTom AI · Accepted Answer

Begin by identifying the given hydrological quantities and converting them to consistent units.
First, compute the total volume of flow (runoff) over the 3-hour period: discharge = 10 m3/s, duration = 3 hours = 3 × 3600 = 10800 seconds. So runoff volume = 10 m3/s × 10800 s = 108000 m3.
Next, relate rainfall to the catchment area. The total rainfall depth is 10.8 mm, which equals 0.0108 meters. If this rainfall produced the measured runoff over the catchment area, then the volume of rainfall received equals rainfall depth × catchment area: 0.0108 m × A = 108000 m3, where A is the catchment area in square meters.
Solve for A: A = 108000 m3 / 0.0108 m = 10,000,000 m2 (since 108000 ÷ 0.0108 = 10,000,000).
Finally, convert the area from square meters to hectares. 1 hectare = 10,000 m2, so A = 10,000,000 m2 ÷ 10,000 m2/ha = 1000 ha.
Therefore, the catchment area is 1000 hectares. The units are consistent and the arithmetic steps align with the relationship between discharge volume, rainfall depth, and catchment area.

If the flow from a catchment is 10m3/s for 3 hours and the total rainfall depth is 10.8 mm, what is the catchment area (in ha)? Hint: remember one hectare = 10000m2数值题

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