In the nucleus of there are

Question

BlackTom AI · Accepted Answer

The atomic number (subscript) gives the number of protons, and the mass number (superscript) equals protons + neutrons. For nuclide notation 238 over 92 U: the subscript 92 is the atomic number and the superscript 238 is the mass number.

Step-by-step reasoning:
1. Identify protons: atomic number = 92, so protons = 92.
2. Identify mass number: A = 238.
3. Compute neutrons: neutrons = mass number − protons = 238 − 92.
4. Perform the subtraction: 238 − 92 = (238 − 90) − 2 = 148 − 2 = 146. So neutrons = 146.

Intermediate arithmetic shown: 238 − 92 = 238 − (100 − 8) = 238 − 100 + 8 = 138 + 8 = 146 (equivalently, direct subtraction gives 146).

Why the correct answer is correct:
- The notation 238^92U explicitly encodes 92 protons and a total nucleon count of 238, so the remaining nucleons must be neutrons: 238 − 92 = 146. Therefore the nucleus contains 92 protons and 146 neutrons.

Why the other options are incorrect:
- (a) “238 protons and 92 neutrons” swaps mass and atomic numbers; 238 is the mass number, not the proton count.
- (b) “92 protons and 238 neutrons” would give a mass number of 330 (92 + 238), which does not match 238.
- (c) “146 protons and 92 neutrons” swaps the proton and neutron counts; the atomic number 92 fixes protons = 92, not 146.

Conclusion: The nucleus of 238^92U contains 92 protons and 146 neutrons, matching answer d.

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