Study the following code. What is the value returned by the function called myArray?

void setup() {
int x = 3;
int y = myArray();
}

void loop() {
delay(500);
}

int myArray() {
int a[7] = {3, 4, 5, 6, 7, 8, 9};
return a[2];
}

Question

Study the following code. What is the value returned by the function called myArray?

void setup() {
  int x = 3;
  int y = myArray();
}

void loop() {
  delay(500);
}

int myArray() {
  int a[7] = {3, 4, 5, 6, 7, 8, 9};
  return a[2];
}

BlackTom AI · Accepted Answer

To determine the value returned by myArray(), we need to follow what the function does.

First, inside myArray(), there is a local array declaration: int a[7] = {3, 4, 5, 6, 7, 8, 9}; This creates seven integers in the function's stack frame with the values 3, 4, 5, 6, 7, 8, 9 in order.

Next, the function executes return a[2]; Here, a[2] refers to the third element of the array (array indices start at 0). The third element is 5. Therefore, the function returns the integer 5.

A few clarifications that sometimes cause confusion: although a is a local array and goes out of scope when the function returns, the value being returned is an int (a single value), not the array itself. Returning an int from a function is perfectly valid, and the caller (setup) will receive that value. In setup, int y = myArray(); assigns the returned value 5 to y.

If you’re thinking about what would happen if you tried to return the array itself, that would be a different scenario (and not allowed in C/C++ as written), but here the code returns a single int element, which is 5.

Study the following code. What is the value returned by the function called myArray? void setup() { int x = 3; int y = myArray(); } void loop() { delay(500); } int myArray() { int a[7] = {3, 4, 5, 6, 7, 8, 9}; return a[2]; }简答题

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