Question at position 5 Which pair of solutions is NOT a buffer upon mixing? Which pair of solutions is NOT a buffer upon mixing? 1 L of 1.5 M NaClO2 mixed with 1 L of 0.5 M HBr1 L of 1 M NaClO2 mixed with 1 L of 0.5 M HI1 L of 1 M HClO3 mixed with 1 L of 0.5 M NH310 L of 1 M NaClO2 mixed with 1 L of 0.5 M HClO2

Question

BlackTom AI · Accepted Answer

We’re asked to identify which mixture is NOT a buffer after mixing two solutions.
Option 1: 1 L of 1.5 M NaClO2 with 1 L of 0.5 M HBr. NaClO2 provides the conjugate base ClO2– and HBr is a strong acid. When these are mixed, the strong acid can protonate ClO2– to form HClO2 (a weak acid). The resulting system contains a weak acid (HClO2) and its conjugate base (ClO2–), which is the classic buffer scenario. Therefore this mixture can act as a buffer, so this option is not the non-buffer.
Option 2: 1 L of 1 M NaClO2 with 1 L of 0.5 M HI. Similar logic applies: HI is a strong acid, which will protonate ClO2– to generate HClO2, leaving a mixture that includes HClO2 and ClO2–. This constitutes a buffer pair, so this option is also a buffer, not the non-buffer.
Option 3: 1 L of 1 M HClO3 with 1 L of 0.5 M NH3. Here HClO3 is a strong acid, and NH3 is a weak base. When mixed, NH3 will be protonated to NH4+ by the strong acid, and there is little or no NH3 left to maintain a buffering system. Moreover, HClO3 is a strong acid whose conjugate base ClO3– is far from being involved in a buffering equilibrium with NH3/NH4+. As a result, this combination does not establish a practical acid–base buffer.
Option 4: 10 L of 1 M NaClO2 mixed with 1 L of 0.5 M HClO2. NaClO2 provides ClO2– (base), and HClO2 is a weak acid. Their mixture forms the conjugate acid–base pair HClO2/ClO2– in appreciable amounts, yielding a true buffer system. So this option is a buffer.
In summary, options 1, 2, and 4 each involve a weak acid–conjugate base pair that can resist pH change to some extent, forming buffers, while option 3 lacks a viable buffering pair due to reaction of NH3 with a strong acid and insufficient base to sustain a buffer system. Consequently, option 3 is the NOT-a-buffer scenario among the choices.

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