Question textConsider two lines \((-1,1,−2)+s(2,1,-2)\) and \((1,2,-1)+t(0,1,-1)\).a) A normal vector to both lines is \((1,\)Answer 1 Question 2[input], Answer 2 Question 2[input]\()\).b) The vector from \((1,2,-1)\) to \((-1,1,−2)\) is \((\) Answer 3 Question 2[input], Answer 4 Question 2[input], Answer 5 Question 2[input] \()\).c) The distance between the two lines is Answer 6 Question 2[input].多项填空题

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Question text Let \[ \mathbf{v} = \langle 6,-3,2 \rangle. \] Then \( | \mathbf{v} | = \) Answer 1 Question 5[input]. Now consider a unit vector \( \mathbf{\hat{v}} \) in the directon of \( \mathbf{v} \). The z-coordinate of \( \mathbf{\hat{v}} \) can be written as a fraction in simplest form as \( \frac{p}{q} \) where \( p, q \) are integers. Then \( p = \) Answer 2 Question 5[input] and \( q = \) Answer 3 Question 5[input].

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