Part 1A credit card company operates two customer service centers. Callers to the service centers dial a single number, and a computer program routes callers to the center having the fewest calls waiting. As part of a customer service review program, the credit card center would like to determine whether the average length of a call (not including hold time) is different for the two centers. The managers of the customer service centers are willing to assume that the populations of interest are normally distributed with equal variances. Suppose a random sample of phone calls to the two centers is selected and the results that were reported are shown below. Complete parts a and b.[table] | Center A | Center B Sample Size | 115115 | 140140 Sample Mean (seconds) | 57.657.6 | 66.766.7 Sample St. Dev. (seconds) | 6.46.4 | 6.46.4 [/table] Part 1a. Using the sample results, develop an 8080% confidence interval estimate for the difference between the two population means. Let sample 1 be the sample from Center A and let sample 2 be the sample from Center B.[input]enter your response here less than or equals≤left parenthesis mu 1 minus mu 2 right parenthesisμ1−μ2less than or equals≤[input]enter your response here (Round to two decimal places as needed.)Multiple fill-in-the-blank
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