Question text 10Marks Consider the system of equations in the variables [math: x,y]x, y and [math: z]: [math: x+y+z=0x+(k+1)y+kz=−2−x+(k2−1)y+(2k−3)z=−4] \matrix{x+y+z=0 \cr x+(k+1)y+kz=-2 \cr -x+(k^2-1)y+(2k-3)z=-4} (a) When the parameter [math: k=−1]k=-1, the system has a solution [math: x=] Answer 1[input], [math: y=] Answer 2[input], [math: z=] Answer 3[input]. (b) When [math: k=0], the system has Answer 4[select: , a unique solution., no solution., infinitely many solutions.] (c) The system has infinitely many solutions when [math: k=] Answer 5[input] and [math: k=] Answer 6[input] (enter your answers in increasing order). (d) The system has no solution when [math: k=] Answer 7[input].Notes Report question issue Question 3 Notes多项填空题