Question at position 1 Given the figure below where light travels from one medium to another, and with Snell's Law in mind as well as the difference between the angles apparent; what is the relationship between the refractive indices n_1 and n_2? n_1 > n_2n_1 < n_2n_1 = n_2Not enough information单项选择题
A
n_1 > n_2
B
n_1 < n_2
C
n_1 = n_2
D
Not enough information

Question

Question at position 1 Given the figure below where light travels from one medium to another, and with Snell's Law in mind as well as the difference between the angles apparent; what is the relationship between the refractive indices n_1 and n_2? n_1 > n_2n_1 < n_2n_1 = n_2Not enough information单项选择题

A

n_1 > n_2

B

n_1 < n_2

C

n_1 = n_2

D

Not enough information

BlackTom AI · Accepted Answer

The problem asks for the relationship between the refractive indices n1 and n2 when light goes from one medium to another and the angle of refraction is larger than the angle of incidence (the ray bends away from the normal in the second medium). First, recall Snell's Law: n1 sin(theta1) = n2 sin(theta2). If the ray bends away from the normal, then theta2 > theta1, which means sin(theta2) > sin(theta1). Since sin(theta1) and sin(theta2) are multiplied by n1 and n2 respectively to give the same product, having sin(theta2) > sin(theta1) while maintaining equality requires n2 < n1. Therefore, n1 is greater than n2 (n1 > n2). Now evaluate the other options: - n1 < n2 would yield theta2 < theta1 (the ray would bend toward the normal), which is not what the figure shows. - n1 = n2 would imply theta1 = theta2 (no bending), also inconsistent with the diagram. - Not enough information would be incorrect here because the figure provides the key detail that theta2 > theta1, allowing a definite comparison of n1 and n2. In summary, the visual cue of refraction away from the normal combined with Snell's Law leads to the conclusion that n1 > n2.

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