Kolme vastusta R1=54 Ω, R2=124 Ω ja R3= 216 Ω kytketään rinnan. Laske systeemin kokonaisresistanssi kahden desimaalin tarkkuudella. Yksikkö ei tarvitse lisätä vastauksen perään.Three resistors R1=54 Ω, R2=124 Ω ja R3= 216 Ω are connected parallel. Calculate the total resistance with two decimal accuracy. Give the answer without unit.

Question

BlackTom AI · Accepted Answer

A system of resistors in parallel follows the relation 1/R_total = 1/R1 + 1/R2 + 1/R3. 
First, convert each resistance to its reciprocal: 1/R1 = 1/54 ≈ 0.0185185, 1/R2 = 1/124 ≈ 0.0080645, and 1/R3 = 1/216 ≈ 0.0046296. 
Next, add these reciprocals together: 0.0185185 + 0.0080645 + 0.0046296 ≈ 0.0312126. 
Then take the reciprocal of the sum to find the total parallel resistance: R_total = 1 / 0.0312126 ≈ 32.04. 
Thus, the total resistance of the parallel combination is approximately 32.04 (to two decimals).

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