If you execute the following code one line at a time, R will return 5.

Hint: There are some restrictions
Links to an external site.
on how you can name an object in R.

a

Question

If you execute the following code one line at a time, R will return 5.

Hint: There are some restrictions
Links to an external site.
 on how you can name an object in R.

a <- 3

b <- 2

else <- 2 * (a + b)

else / 2

BlackTom AI · Accepted Answer

The question asks us to consider what R would return when executing the given code line by line, noting there are naming restrictions for objects in R.
Option 1: True. This would imply that the code yields 5. However, the critical issue here is the object name 'else'. In R, 'else' is a reserved word used in control flow (if... else). As a result, trying to assign to a variable named else without backticks is not allowed, and the code will fail at the line else <- 2 * (a + b). Therefore, the statement that R will return 5 is incorrect because the naming restriction prevents successful execution of that line, so you do not even reach the final division by 2 to produce 5.
Option 2: False. This statement claims that the code does return 5. The main obstacle is the invalid object name 'else'. Since 'else' is reserved, the assignment will produce a syntax/parse error before the calculation can complete, so the code cannot return 5 as written. This aligns with the idea that the claim is not true given the naming rule.
Additional nuance: if you really wanted to use a name that looks like a keyword, you could backtick the name, e.g., `else` <- 2 * (a + b); then evaluating else / 2 would yield 5. But without backticks, the code as provided cannot execute successfully, so the overall statement that it returns 5 is false.
In short, the restriction on naming is the decisive factor, making the True option incorrect and the False option correct in the sense of the code as written.

If you execute the following code one line at a time, R will return 5. Hint: There are some restrictions Links to an external site. on how you can name an object in R. a <- 3 b <- 2 else <- 2 * (a + b) else / 2判断题

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