Chai walks to college 60% of the time. Vy does the same 30% of the time. Considering these events as independent, the probability that both students walk to college is:Single choice
A
A. 0.18
B
B. 0.90
C
C. 0.60
D
D. 0.30

Question

Chai walks to college 60% of the time. Vy does the same 30% of the time. Considering these events as independent, the probability that both students walk to college is:

BlackTom AI · Accepted Answer

For independent events, the probability that both occur equals the product of their individual probabilities. Chai walks 60% = 0.60 and Vy walks 30% = 0.30, so compute the product.

Step-by-step calculation:
- Convert percentages to decimals/fractions: 60% = 0.60 = 3/5, 30% = 0.30 = 3/10.
- Multiply: 0.60 × 0.30 = (3/5) × (3/10) = 9/50.
- Convert to decimal/percent: 9/50 = 0.18 = 18%.

Thus the joint probability that both students walk is 0.18.

Why this is correct: independence means Chai’s choice does not affect Vy’s; therefore the joint probability is the product of the two independent probabilities. Multiplication gives the probability both events happen together.

Why the other choices are incorrect:
- 0.90 (B): This looks like a mistaken sum 0.60 + 0.30 = 0.90. Adding probabilities of two events is not correct for “both” (addition would overcount the overlap). The correct probability that at least one walks would be 1 − P(neither) = 1 − (0.40 × 0.70) = 1 − 0.28 = 0.72, not 0.90.
- 0.60 (C): This is just Chai’s probability alone, not the probability both walk.
- 0.30 (D): This is just Vy’s probability alone, not the joint probability.

Conclusion: The correct answer is A. 0.18, which matches the provided answer.

Chai walks to college 60% of the time. Vy does the same 30% of the time. Considering these events as independent, the probability that both students walk to college is:Single choice

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