On the phase diagram below the triple point is (1) , the critical point is (2) , and the line representing melting is (3) .

Question

On the phase diagram below the triple point is   (1) , the critical point is   (2)  , and the line representing melting is   (3)  .

BlackTom AI · Accepted Answer

To reason through this phase diagram question, I will evaluate each labeled feature and map it to the most plausible descriptor given in the options.
Option A: (1): E (2): D (3): A to F
- Triple point corresponds to the unique condition where solid, liquid, and gas coexist. In the diagram, the G point sits at the intersecting region of the three phases and is the only point that would typically represent a triple point, not E. Therefore labeling (1) as E is unlikely to be correct.
- The critical point is where the liquid-gas boundary ends; in diagrams like this, that endpoint is typically a high-temperature, high-pressure point. D is a high-T, high-P point on the curve, but without seeing the exact end of the critical boundary, assigning D to the critical point is speculative.
- The melting line is the solid-liquid boundary, which is usually a relatively flat horizontal line at low to moderate pressures. In this diagram the horizontal solid-liquid boundary would align with the A–B region, not A–F, so choosing A to F misidentifies the melting line.
Option B: (1): G (2): D (3): A to B
- This option assigns the triple point to G, which matches the common interpretation where G sits at the junction of solid, liquid, and gas phases.
- The critical point being D fits if D is at the terminus of the liquid–gas boundary on the diagram’s upper-right section, which is plausible for a labeled D point on the curve.
- The melting line as A to B corresponds to the solid–liquid boundary between A and B along a horizontal path; that aligns with typical melting boundaries in phase diagrams, making A to B a reasonable melt path.
Option C: (1): D (2): G (3): A to B
- Here the triple point is labeled D, but the triple point is not typically at D in this diagram since G appears to be at the junction of all three phases. This makes the choice inconsistent with the phase-boundary geometry.
- If G is the triple point, then assigning G to the critical point (2) would also be incorrect because the critical point is generally not at the triple junction.
- The melting line A to B is plausible, but the misassignment of the triple point and critical point already makes this option unreliable.
Option D: (1): G (2): D (3): A to F
- While (1) G for the triple point is acceptable, (3) A to F would imply the melting boundary runs from A to F, which is inconsistent with the diagram’s horizontal solid–liquid segment that more naturally aligns with A to B.
- Since the melting line is not A to F, this option is unlikely.
Option E: (1): E (2): D (3): A to B
- Assigning the triple point to E contradicts the diagram where G sits at a three-phase intersection, making this option incorrect.
- The rest of the option (2) and (3) align with the previous plausible mapping, but the incorrect triple point makes this option invalid.
In summary, considering which labeled point sits at the three-phase intersection, which point lies at the end of the liquid–gas boundary (critical point), and which path represents the solid–liquid boundary (melting line), the option that consistently aligns each label with the phase-boundary roles is: (1) G for the triple point, (2) D for the critical point, and (3) A to B for the melting line. Therefore, the correct choice is the one that lists (1): G, (2): D, (3): A to B.

On the phase diagram below the triple point is (1) , the critical point is (2) , and the line representing melting is (3) . 单项选择题

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