Question textConsider the following chemical reaction: C6H6 (l) + 3 H2 (g) → C6H12 (l) In this reaction, the entropy: Answer 1 Question 2[select: , increases, decreases, does not change] because Answer 2 Question 2[select: , gases have higher entropy than solids, gases have higher entropy than liquids] and Answer 3 Question 2[select: , the number of moles of gas decreases, the number of moles of gas increases]

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BlackTom AI · Accepted Answer

In the given chemical reaction, C6H6 (l) + 3 H2 (g) → C6H12 (l), the entropy decreases. This is because gases generally have higher entropy than liquids due to their greater molecular freedom and disorder. In this reaction, three moles of gaseous hydrogen (H2) are consumed to form a liquid product (C6H12). The transition from gas to liquid involves a decrease in entropy as the molecules in the liquid phase are more ordered compared to the gaseous phase. Additionally, the number of moles of gas decreases from three moles of H2 to zero moles of gas in the product, further contributing to the overall decrease in entropy.

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