The specific heat capacity of an exotic metal is 45J.kg-1.°C-1. How much heat energy (in J) is required to raise the temperature of 18kg of this material by 46°C? Only put in the numerical value. Do not write the unit in your answer.

Question

BlackTom AI · Accepted Answer

Start by identifying the formula for heat required at constant pressure, which is Q = m c ΔT.
Next, note the given quantities: mass m = 18 kg, specific heat capacity c = 45 J/(kg·°C), and temperature change ΔT = 46 °C.
Compute the product step by step: first multiply mass by specific heat, m × c = 18 × 45.
18 × 45 equals 810 (since 18 × 40 = 720 and 18 × 5 = 90; 720 + 90 = 810).
Then multiply this result by the temperature change: 810 × 46.
Break it down further: 810 × 46 = 810 × (40 + 6) = (810 × 40) + (810 × 6) = 32400 + 4860 = 37260.
Thus, the heat energy required is the product 37260, following the units implied by the calculation (Joules).
If you were to verify with unit handling: m in kg times c in J/(kg·°C) gives J/°C, and multiplying by ΔT in °C yields J, as expected.

The specific heat capacity of an exotic metal is 45J.kg-1.°C-1. How much heat energy (in J) is required to raise the temperature of 18kg of this material by 46°C? Only put in the numerical value. Do not write the unit in your answer.简答题

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