Consider the following schema:
#Suppliers(sid: integer, sname: string, address: string)
#Parts(pid: integer, pname: string, color: string)

#Makers(mid: integer, mname: string)
#Catalog(sid: integer, pid: integer, mid integer,cost: integer)

It is created using following

CREATE TABLE Suppliers
( sid integer NOT NULL, sname varchar (25) NOT NULL, address varchar (25), PRIMARY KEY (sid) );

CREATE TABLE Parts

( pid integer NOT NULL, pname varchar (25) NOT NULL, color varchar (25) NOT NULL, PRIMARY KEY (pid) );

CREATE TABLE Makers

( mid integer NOT NULL, mname varchar (25) NOT NULL, PRIMARY KEY (mid) );

CREATE TABLE Catalog

( sid integer NOT NULL, pid integer NOT NULL,mid integer NOT NULL, cost integer, PRIMARY KEY (sid,pid,mid),
FOREIGN KEY (sid) REFERENCES Suppliers(sid),
FOREIGN KEY (pid) REFERENCES Parts(pid),

FOREIGN KEY (mid) REFERENCES Makers(mid) );

Here sid is the primary key for Suppliers, pid is the primary key for Parts, and (sid, pid, mid)
together form the primary key for Catalog. The Catalog relation lists the prices charged for
parts.

Parts.color can take values "Red", "Blue", "Yellow" etc.

Write one SQL query to find the sids of suppliers who supply all color "Red" parts in the table Parts.

Please type your answer.

Question

Consider the following schema:
#Suppliers(sid: integer, sname: string, address: string)
#Parts(pid: integer, pname: string, color: string)

#Makers(mid: integer, mname: string)
#Catalog(sid: integer, pid: integer, mid integer,cost: integer)

It is created using following

CREATE TABLE Suppliers
( sid integer NOT NULL, sname varchar (25) NOT NULL, address varchar (25), PRIMARY KEY (sid) );

CREATE TABLE Parts

( pid integer NOT NULL, pname varchar (25) NOT NULL, color varchar (25) NOT NULL, PRIMARY KEY (pid) );

CREATE TABLE Makers

( mid integer NOT NULL, mname varchar (25) NOT NULL, PRIMARY KEY (mid) );

CREATE TABLE Catalog

( sid integer NOT NULL, pid integer NOT NULL,mid integer NOT NULL, cost integer, PRIMARY KEY (sid,pid,mid), 
FOREIGN KEY (sid) REFERENCES Suppliers(sid),
FOREIGN KEY (pid) REFERENCES Parts(pid),

FOREIGN KEY (mid) REFERENCES Makers(mid) );

Here sid is the primary key for Suppliers, pid is the primary key for Parts, and (sid, pid, mid)
together form the primary key for Catalog. The Catalog relation lists the prices charged for
parts.

Parts.color can take values "Red", "Blue", "Yellow" etc.

Write one SQL query  to find the sids of suppliers who supply all color "Red" parts in the table Parts.

Please type your answer.

BlackTom AI · Accepted Answer

The task is to identify suppliers that supply all parts whose color is Red. The provided SQL uses a classic NOT EXISTS pattern to express this universal-quantification requirement.

First, the outer query selects sid from Suppliers (aliased as S). The WHERE clause uses NOT EXISTS with a correlated subquery involving Parts (aliased P) and Catalog (aliased C).

Explanation of the logic step by step:
- The inner subquery:
  SELECT P.pid FROM Parts P WHERE P.color = 'Red' AND NOT EXISTS (SELECT * FROM Catalog C WHERE C.sid = S.sid AND C.pid = P.pid)
  This subquery looks at every part P that has color 'Red'. For a given supplier S.sid, it checks whether there exists a red part P.pid for which there is no catalog entry (C) that ties S.sid to P.pid. In other words, it asks: Is there a red part that this supplier does NOT supply?
- The NOT EXISTS on the inner subquery flips that question to: Are there no red parts for which the supplier lacks a catalog entry? If true, then the supplier supplies every red part.
- The outer NOT EXISTS around that inner subquery means: for the given S.sid, there is no red part that the supplier does not supply. If that condition holds, S.sid is returned by the query.

Why this yields the desired result:
- For each supplier, the query verifies coverage of every red-colored part listed in Parts. If any red part is missing from the supplier's catalog entry (Catalog), the NOT EXISTS condition fails and the supplier is excluded.
- Conversely, if the supplier has catalog entries for all red parts (i.e., for every red P.pid there exists a row in Catalog with that sid and pid), the NOT EXISTS condition is satisfied, and the supplier is included.

Edge cases and nuances:
- If there are no red parts in the Parts table, the inner condition P.color = 'Red' yields an empty set. The NOT EXISTS on an empty set is true, so every supplier satisfies the condition and would be returned. This is consistent with the interpretation that every supplier supplies all (zero) red parts.
- The query only checks existence in Catalog by sid and pid; it ignores mid and cost. That aligns with the problem statement, which asks whether suppliers supply all red parts, regardless of maker or price. If you additionally needed to ensure a specific maker or multiple conditions, you’d expand the JOIN/WHERE clauses accordingly.
- Performance considerations: this pattern can be expensive on large datasets because it runs a nested NOT EXISTS across all red parts for each supplier. An alternative approach is to use aggregation: join Suppliers to Catalog to red Parts, group by sid, and require count(distinct pid) = count(distinct red_pid) for each sid. However, the NOT EXISTS approach is straightforward and semantically correct for the stated requirement.

In summary, the query correctly identifies all supplier IDs that supply every red part listed in the Parts relation by ensuring there is no red part that a supplier does not supply.

类似问题

Question 30 Choose a, b, c or d as the best answer. The author’s main argument is that the 100:80:100 model __________.

Write ONE OR TWO WORDS from the text to complete the sentence. 24. ‘their’ in paragraph 5 refers to Answer Question 12[input].

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