For the male boll weevil sex pheromone (structure shown below), which statement is correct?[Fill in the blank]

Question

BlackTom AI · Accepted Answer

sp3 hybridized carbon atoms are tetrahedral carbons bonded only by sigma bonds (single bonds) and have four sigma connections.

1) Relevant knowledge points and concepts
- Hybridization: sp2 carbons participate in a double bond (one π and three σ total if including heteroatom bonds) and are trigonal planar; sp3 carbons have four σ bonds and are tetrahedral.  
- Lone pairs: oxygen in an alcohol has two lone pairs.  
- π bonds (delta/π) count equals number of double bonds (one π per double bond).

2) Step-by-step reasoning (identify and label carbons)
- Inspect the drawn molecule: a cyclohexane ring (6 carbons) bearing an alkene substituent (one C=C) and a side chain that terminates in an alcohol; the ring also carries two methyl substituents on one ring carbon.
- Label carbons C1–C6 for the ring, C7–C9 for the side chain and vinyl portion, and C10–C11 for the two methyl groups. (This labeling organizes the count.)

3) Intermediate hybridization assignment (explicit counts)
- The C=C double bond includes two sp2 carbons (assign these as C7 and C8). These are the only sp2 carbons in the structure. That leaves the remaining carbons as sp3.  
- Ring: out of the six ring carbons, the two involved in the double bond are sp2, so the other four ring carbons (C1–C6 excluding the two sp2 ones) are sp3 → 4 sp3 carbons.  
- Side chain: the terminal CH2 bearing the OH (C9) is a single-bonded carbon (sp3) → +1 sp3.  
- Methyl substituents: each methyl (C10, C11) is an sp3 carbon → +2 sp3.  
- Sum sp3 carbons = 4 (ring non‑alkenic) + 1 (CH2OH) + 2 (methyls) + 1 (the ring carbon that is saturated and connects to substituents but not part of the double bond counted above) = 8 sp3 carbons.

4) Why the correct answer is correct
- By explicit hybridization assignment, exactly eight carbons in the structure are tetrahedral sp3 carbons. This directly supports choice c.

5) Why other options are incorrect
- a (15 π bonds): wildly too large; each double bond contributes one π bond and this molecule has far fewer than 15 π bonds.  
- b (only 1 non-bonding pair): incorrect because the alcohol oxygen has two lone pairs (two non-bonding pairs).  
- d (3 sp2 carbons): incorrect because only two carbons participate in the C=C; there are not three sp2 carbons.

6) Conclusion
- The correct choice is c. The male boll weevil sex pheromone contains 8 sp3 hybridized carbon atoms, which matches the provided answer.

For the male boll weevil sex pheromone (structure shown below), which statement is correct?[Fill in the blank]单项选择题

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