An experiment requires you to create a stock buffer containing 0.06 M of NaOH in a total volume of 350 mL.How many grams (g) of solid NaOH are required to prepare this stock solution?Note: Your answer should be to two decimal places, e.g. 4.31

Question

BlackTom AI · Accepted Answer

The task is to prepare a stock buffer with a concentration of 0.06 M NaOH in a total volume of 350 mL. To find the mass of solid NaOH needed, start by converting the volume to liters: 350 mL = 0.350 L. Then compute the number of moles required using the molarity formula: moles = M × V = 0.06 mol/L × 0.350 L = 0.0210 mol. Next, convert moles to grams using the molar mass of NaOH. NaOH has a molar mass of approximately 23.0 (Na) + 16.0 (O) + 1.0 (H) ≈ 40.0 g/mol. Multiply the moles by the molar mass: 0.0210 mol × 40.0 g/mol = 0.840 g. Finally, round to two decimal places as requested: 0.84 g. Note: If there were any rounding differences in the molar mass used, you might see a very small variation, but with 40.0 g/mol and the given figures, 0.84 g is the result to two decimals. Additionally, since the question provides a numerical answer rather than multiple choices, this calculation shows each step clearly from volume and concentration to the final mass. Be mindful of sign conventions and units at every step to avoid errors in a lab setting.

An experiment requires you to create a stock buffer containing 0.06 M of NaOH in a total volume of 350 mL.How many grams (g) of solid NaOH are required to prepare this stock solution?Note: Your answer should be to two decimal places, e.g. 4.31数值题

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